If I have an array of arrays (a matrix) in python, e.g.
my_array = [[1,2,3],[4,5,6],[7,8,9],[1,2,3]]
and I would like to remove all instances of [1,2,3]
new_array = my_array.remove([1,2,3])
results in null. Is there a way to apply remove() to arrays within arrays in this way that would work, i.e. so that
new_array = [[4,5,6],[7,8,9]]
my_array = [[1,2,3],[4,5,6],[7,8,9],[1,2,3]]
# you can put your conditions
new_array = [arr for arr in my_array if [1,2,3] != arr]
print(new_array)
The remove() doesn't return any value (returns None). Also, you have defined a list of list, not array. You should write it this way:-
my_array = [[1,2,3],[4,5,6],[7,8,9],[1,2,3]]
count = my_array.count([1,2,3]) # returns 2
for i in range(count):
my_array.remove([1,2,3])
print(my_array)
Output:-
[[4, 5, 6], [7, 8, 9]]
You can use a loop and remove function to get the desired result
my_array = [[1,2,3],[4,5,6],[7,8,9],[1,2,3]]
while([1,2,3] in my_array):
my_array.remove([1,2,3])
print(my_array)
