How to remove a specific element from a 2d array in Python?

Question

I am new to Python and now I'm trying to create a game called Pong

Everything looks to work fine but unfortunately, I can't remove a specific element from 2D-Array /List once the ball touches a brick.

Here is my code:

class Brick:
    size = 5
    bricks = [[0] * size for i in range(size)] 

    def __init__(self, x, y):
        self.x = x
        self.y = y

    def createBricks(self):
        for x in range(self.size):
            for y in range(self.size):
                self.bricks[x][y] = Brick(x * 70, y * 40)

    def draw(self):
        for bricks in self.bricks:
            for brick in bricks:
                 rect(brick.x, brick.y, 50, 20)

In the following method, I want to remove the specific element:

#In my main class

def removeBrick():
    for elem in brick.bricks:
        for _brick in elem:
            if ball.touchesBrick(_brick.x, _brick.y):
               #Here I want to remove the element

I have tried many ways with remove() and del but as a result, I couldn't solve it.

Thanks in advance.

Amin Guermazi · Accepted Answer · 2020-06-12 10:39:36Z

1

using for loops just gives you a copy to the element (so you can't modify it directly). To solve this problem, you should use the enumerate class:

def removeBrick():
    for elem in brick.bricks:
        for i, _brick in enumerate(elem):
            if ball.touchesBrick(_brick.x, _brick.y):
               _brick.pop(i)

answered Jun 12, 2020 at 10:39

Amin Guermazi

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2 Comments

Hashmat Over a year ago

Thanks for the answer but, after running your solution it throws the following error: AttributeError: Brick instance has no attribute 'pop'

H4kim Over a year ago

I think Amin should have written elem.pop(i) (elem is the list of Brick from which you want to remove stuff while _brick is an element of it so it doesn't have a pop method implemented).

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