How to find an element with respect to the user input using Selenium and Python?

Question

The following is the HTML structure:

<div class='list'>
  <div>
    <p class='code'>12345</p>
    <p class='name'>abc</p>
  </div>
  <div>
    <p class='code'>23456</p>
    <p class='name'>bcd</p>
  </div>
</div>

And there is a config.py for user input. If the user input 23456 to config.code, how can the selenium python select the second object? I am using find_by_css_selector() to locate and select the object, but it can only select the first object, which is Code='12345'. I tried to use find_by_link_text(), but it is a <p> element not <a> element. Anyone can help.....

@LoganGeorge No. One div means one object, I want to select the second object which code is 23456 and name is bcd. — Tony Chan
– Tony Chan, Commented Jun 4, 2020 at 7:33

undetected Selenium · Accepted Answer · 2020-06-04 20:13:06Z

To locate the element with respect to the input by the user using Selenium and python you need to to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

Using variable in XPATH:

user_input = '23456'
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='list']//div/p[@class='code' and text()='" +user_input+ "']")))

Using %s in XPATH:

user_input = '23456'
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='list']//div/p[@class='code' and text()='%s']"% str(user_input))))

Using format() in XPATH:

user_input = '23456'
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='list']//div/p[@class='code' and text()='{}']".format(str(user_input)))))

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

frianH · Accepted Answer · 2020-06-04 08:15:27Z

1

Try the below xpath:

code = '23456'
element = driver.find_element_by_xpath("//p[@class='code' and text()='" +code +"']")

edited Jun 4, 2020 at 8:15

answered Jun 4, 2020 at 7:37

frianH

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6 Comments

Logan George Over a year ago

Right. Then to get the sibling I think it would be driver.find_element_by_xpath("//p[@class='code' and text()='" +code +"']/following-sibling::p")

Tony Chan Over a year ago

@frianH it wokrs! But i am not really understand the use of xpath. Can you explain more on "//p[@class='code' and text()='" +code +"']" ?

Tony Chan Over a year ago

@LoganGeorge what's the meaning of sibling u are talking?

frianH Over a year ago

@YukChan that's just simple logic using the AND expression. Trying search for a p tag with the class name is code and the tag has the text 23456.

frianH Over a year ago

@YukChan it's for string merger.

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