How to populate an array dynamicaly using a loop in PHP?

Question

How to populate an array dynamicaly using a for loop in PHP?

eg: Here is an array...

    static protected $db_columns = [' ',' '];

... and here is the for loop

    $qcount = 4;
    for($i=1; $i<=$qcount; $i++) {

The array should become

     static protected $db_columns = ['1','2',3','4'];

Depending on the $qcount the array should expand. Please help.

Start with an empty array $db_columns = [] and add items with $db_columns[] = $value. It will expand by itself. — Michel
– Michel, Commented May 27, 2020 at 5:47
Does this answer your question? PHP - populate an array with variables by loop — Fourier
– Fourier, Commented May 27, 2020 at 5:59

sachin kumara liyanage · Accepted Answer · 2020-05-27 05:56:13Z

1

you can initialize array like this

$db_columns = array();

add value using a loop

$qcount = 4;
for($i=1; $i<=$qcount; $i++) {
 array_push($db_columns,$i);
}

and after loop, you can check with printing array

var_dump($db_columns);

answered May 27, 2020 at 5:56

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