Python NumPy shape

Question

Can someone please explain this code to me

case = np.array([[1,2], [2,4], [3,5]])

I understand the above gives 2 columns and 3 rows.

But the code below I don't understand. Please help me to understand it.

np.arange(0, case.shape[0]+4)

case.shape is (2,3), case.shape[0] is 2, so the code is just np.arange(6). — Quang Hoang
– Quang Hoang, Commented May 21, 2020 at 13:23
@QuangHoang. Aside from the shape being (3, 2), you are absolutely correct — Mad Physicist
– Mad Physicist, Commented May 21, 2020 at 20:16

yatu · Accepted Answer · 2020-05-21 13:32:33Z

1

np.arange() returns evenly spaced values within a given interval.

In this case, since case.shape[0] is the first axis of the array, which has 3 arrays in it, the range goes from 0 to 3+4=7 (end not included).

edited May 21, 2020 at 13:32

yatu

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answered May 21, 2020 at 13:22

Red

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Aman · Accepted Answer · 2020-05-21 13:32:24Z

0

case = np.array([[1,2], [2,4], [3,5]])
case
array([[1, 2],
   [2, 4],
   [3, 5]])

Numpy.arange will provide a series of numbers starts from 0 to case.shape[0] +4 . Here case.shape is (3,2) (Three Rows and Two Columns) . So Case[0] will be 3 and case[1] will be 2 . So np.arrange will be a series of numbers from 0 to 3+4 = 7 where 0 is included and 7 is excluded and output will be 0,1,2,3,4,5,6

answered May 21, 2020 at 13:32

Aman

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