How to modify a value in array of object's based on other object

Question

i have an object as :

let sample = {cat: 10 , dog: 50 , snake: 25};

I have the array of object as :

let petarray = [
    {name: 'newcat' , quantity: 20},
    {name: 'oldcat' , quantity: 15},
    {name: 'razordog' , quantity: 10}
];

May I know how can I modify the petarray quantity such that if petarray[allindexes].name includes any of sample , then quantity = quantity * (respective number of sample )

for eg: petarray[0].name includes cat , the quantity should be modified as 20*(10)

any help on how to achieve is much appreciated ,TIA (hope it is clear)

please let me know for any more info or on what i can do to improve about this result

Vikas Keskar · Accepted Answer · 2020-05-15 07:24:28Z

2

you can try this,

let sample = {cat: 10 , dog: 50 , snake: 25};
let petarray = [{name: 'newcat' , quantity: 20},{name: 'oldcat' , quantity: 15},{name: 'razordog' , quantity: 10}];
let sampleArrayKeys = Object.keys(sample)
petarray = petarray.map((p) =>{
 const key = sampleArrayKeys.find(sak => p.name.includes(sak))
 if (key) {
  p.quantity *= sample[key]
 }
 return p
})

console.log(petarray)

answered May 15, 2020 at 7:24

Vikas Keskar

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3 Comments

KcH Over a year ago

Thanks for the solution mate , i have a weird situation where sample = {cat: 10 , dog: 50 , snake: 25 , venomsnake : 15} and the name:"africavenomsnake" , may i know how this to be matched only with venomsnake not snake

Vikas Keskar Over a year ago

Difficult to define this case, but you can give a shot by considering value of substring of key with max length. In venomsnake and snake example, you can see africavenomsnake has venomsnake with more length than snake.

KcH Over a year ago

yeah mate , good point :) ....may i know how can i check this

Raul Licaret · Accepted Answer · 2020-05-15 07:33:57Z

2

let sample = {cat: 10 , dog: 50 , snake: 25};
let petarray = [{name: 'newcat' , quantity: 20},{name: 'oldcat' , quantity: 15},{name: 'razordog' , quantity: 10}];

petarray.forEach(pet => {    
    for (let sampleKey in sample) {
        if (sample.hasOwnProperty(sampleKey)) {
            if (pet.name.includes(sampleKey)) {
                pet.quantity *= sample[sampleKey];
            }
        }
    }
}, petarray)

console.log(petarray)

answered May 15, 2020 at 7:33

Raul Licaret

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Comments

Abhisar Tripathi · Accepted Answer · 2020-05-15 07:45:21Z

2

It can be done like this -:

let sample = {cat: 10 , dog: 50 , snake: 25};

const sampleKeys = Object.keys(sample);

petarray = petarray.map(item =>
    sampleKeys.find(key => item.name.includes(key))
    ? { ...item, quantity: item.quantity * sample[match] }
    : item;
)

edited May 15, 2020 at 7:45

answered May 15, 2020 at 7:21

Abhisar Tripathi

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3 Comments

KcH Over a year ago

Thanks for the solution mate :) , i have a weird situation where sample = {cat: 10 , dog: 50 , snake: 25 , venomsnake : 15} and the name:"africavenomsnake" , may i know how this to be matched only with venomsnake not snake

Abhisar Tripathi Over a year ago

It will match with the first occurence in the key array, If we need it to match with venomsnake we can ensure the object is like this where venomsnake comes first {cat: 10 , dog: 50 , venomsnake: ##, snake: 25}; and not like this {cat: 10 , dog: 50 , snake: 25, venomsnake: ##};

KcH Over a year ago

Thanks for suggestion , i would try this way :)

StepUp · Accepted Answer · 2020-05-15 07:53:28Z

1

You can create mapping and then just map this array:

let sample = {cat: 10 , dog: 50 , snake: 25};

let petarray = [
    {name: 'newcat' , quantity: 20},
    {name: 'oldcat' , quantity: 15},
    {name: 'razordog' , quantity: 10}
];

const keys = Object.keys(sample);
const mapping = petarray.reduce((a, {name})=>{
    a[name] = a[name] || {};
    let sampleKey = keys.find(k => name.includes(k));
    if (sampleKey)
        a[name] = sampleKey;
    return a;
}, {})


petarray = petarray.map(({name, quantity}) => ({ name,
    quantity: ((sample[mapping[name]] ? (quantity * sample[mapping[name]]) : quantity))}));

console.log(petarray);

answered May 15, 2020 at 7:53

StepUp

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