Generate URL in Symfony 5 with GET parameters

Question

In Symfony 5, I would like to generate an URL partially based on GET paramaters already posted.

Let's assume that the URL posted is:

user/edit/5?foo=1&bar=1&baz=1&qux=1

I would like to generate in the controller without foo:

user/edit/5?bar=1&baz=1&qux=1

First, I remove foo parameter :

$request->query->remove('foo');

If I didn't get the user_id in the URL as route parameter (5), I would use:

$this->generateUrl('user_edit', $request->query->all());

But this is not working because user_id is missing. So how can I generated such URL without rewriting all variables:

$this->generateUrl('user_edit', ['id' => $user->getId(), ???]);

I was thinking about PHP function array_merge() but this seems to me more a trick than an elegant solution:

$this->generateUrl('user_edit', array_merge(
    ['id' => $user->getId()],
    $request->query->all())
);

yivi · Accepted Answer · 2020-05-08 09:08:28Z

3

There is nothing wrong in using array_merge(). That's exactly what you want to accomplish. It's not a "trick", it's a language feature.

If you want a less verbose syntax, just use +.

$this->generateUrl('user_edit', $request->query->all() + ['id' => $user->getId()]);

The end result is exactly the same for the above, and it's shorter.

answered May 8, 2020 at 9:08

yivi

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