Feels like this should be easy, but I can't find the right keywords to search for the answer.
Given ['"https://container.blob.core.windows.net/"'] as results from a python statement...
...how do I extract only the URL and drop the ['" and "']?
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4 Answers
You want the first element of the list without the first and last char
>>> l[0][1:-1]
'https://container.blob.core.windows.net/'
1 Comment
SeaDude
Wow! The smallest amount of code possible. Nice! This worked as well.
How about using regex??
In [35]: url_list = ['"https://container.blob.core.windows.net/"']
In [36]: url = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\), ]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', url_list[
...: 0])[0]
In [37]: print(url)
https://container.blob.core.windows.net/
1 Comment
SeaDude
Thank you. I went with other solutions because the amount of code was less.
try:
a = ['"https://container.blob.core.windows.net/"']
result = a[0].replace("\"","")
print(result)
Result:
'https://container.blob.core.windows.net/'
As a python string.
Comments
How about getting first element using list[0] and remove the single quotes from it using replace() or strip() ?
print(list[0].replace("'",""))
OR
print(list[0].strip("'")
answered May 1, 2020 at 6:06
A l w a y s S u n n y
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2 Comments
SeaDude
I went with your second option as it was the smallest amount of code. Edited a bit with:
url = str(blob_url[0].strip('"')). Had to strip out the doublequote and convert to string. Thanks for your assistance!A l w a y s S u n n y
@SeaDude glad it helps you somehow, Happy Coding!