I have a hash:
row = {
'name' => '',
'description' => '',
'auth' => '',
'https' => '',
'cors' => '',
'url' => ''
}
and I also have an array:
["Cat Facts", "Daily cat facts", "No", "Yes", "No", "https://example.com/"]
How can I grab the array elements and set them as values for each key in the hash?
Let's say row is your hash and values is your array
row.keys.zip(values).to_h
=> {"name"=>"Cat Facts", "description"=>"Daily cat facts", "auth"=>"No", "https"=>"Yes", "cors"=>"No", "url"=>"https://example.com/"}
It works if they are in the right order, of course
h = { 'name'=>'',
'description'=>'',
'auth'=>'',
'https'=>'',
'cors'=>'',
'url'=>'' }
arr = ["Cat Facts", "Daily cat facts", "No", "Yes", "No",
"https://example.com/"]
enum = arr.to_enum
#=> #<Enumerator: ["Cat Facts", "Daily cat facts", "No",
# "Yes", "No", "https://example.com/"]:each>
h.transform_values { enum.next }
#=> { "name"=>"Cat Facts",
# "description"=>"Daily cat facts",
# "auth"=>"No",
# "https"=>"Yes",
# "cors"=>"No",
# "url"=>"https://example.com/" }
See Hash#transform_values. Array#each can be used in place of Kernel#to_enum.
If arr can be mutated enum.next can be replaced with arr.shift.
Given the hash and the array:
row = { 'name' => '', 'description' => '', 'auth' => '', 'https' => '', 'cors' => '', 'url' => '' }
val = ["Cat Facts", "Daily cat facts", "No", "Yes", "No", "https://example.com/"]
One option is to use Enumerable#each_with_index while transforming the values of the hash:
row.transform_values!.with_index { |_, i| val[i] }
row
#=> {"name"=>"Cat Facts", "description"=>"Daily cat facts", "auth"=>"No", "https"=>"Yes", "cors"=>"No", "url"=>"https://example.com/"}
The bang ! changes the original Hash.
