Using a regex to replace characters in a string in an Angular template

Question

I know that I can normally use myString.replace(/\*/g, '') to remove * from a string. But I cannot seem to make that work in a Angular HTML template. Here is what I doing ...

<div class="panel panel--raised">
  <div class="row">
    <div class="form-group col-md-6">
      <div class="form-group__text">
        <input type="text" placeholder="Search... (min of 3 characters)" [(ngModel)]="searchString" minlength="3">
      </div>
    </div>
    <div class="col-md-6">
      <button class="btn btn--success btn--small host-info-button"
              [disabled]="searchString.replace(/\*/g, '').length < 3"
              (click)="getInfo(searchString)">Search</button>
    </div>
  </div>
</div>

Parser Error: Unexpected token / ...

What am I doing wrong here?

Update:

What I am trying to do is make the user enter at least 3 characters that are not wildcard (*) characters. So a** would only count as 1 character and *** would count as zero characters, but *xyz* would count as 3 characters. I am not sure that Validator.pattern() would be able to accomplish this, but maybe I am just lacking imagination.

This feels like a use case for a pattern validator

bryan60
– bryan60

2020-04-23 23:09:30 +00:00
Commented Apr 23, 2020 at 23:09 — bryan60
– bryan60, Commented Apr 23, 2020 at 23:09

Sergej · Accepted Answer · 2020-04-23 23:27:06Z

3

in template:

[disabled]="isDisabled"

in ts file:

get isDisabled(): boolean {
    return this.searchString.replace(/\*/g, '').length < 3;
}

answered Apr 23, 2020 at 23:27

Sergej

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1 Comment

Red Cricket Over a year ago

Ah ... I was just lacking imagination. Thanks this works great!

Naseh Badalov · Accepted Answer · 2020-04-23 23:06:31Z

3

Unfortunately, RegExp literal is not supported by the templating language. They should be on your component.

More info on Angular Github repo issue: https://github.com/angular/angular/issues/21978

For this particular case, you can set up pattern validator and use something like this: Validators.pattern('/\*/g')

edited Apr 23, 2020 at 23:06

answered Apr 23, 2020 at 23:05

Naseh Badalov

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4 Comments

Red Cricket Over a year ago

ug! I want to be able to make the user enter at least 3 characters not counting *'s before they can submit a search. Is there some sort of validation I should set up?

Naseh Badalov Over a year ago

Edited the answer

Red Cricket Over a year ago

Where do I put Validators.pattern(...) in my code?

Naseh Badalov Over a year ago

Please refer to this documentation: angular.io/api/forms/PatternValidator

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