I get:
if(lst[i]%2!=0):
IndexError: list index out of range
from this code:
lst=[1,2,3,4,5,6]
for i in range(len(lst)):
if(lst[i]%2!=0):
lst.remove(lst[i])
print(lst)
I am trying to print only the even numbers in a list and I do not see a problem with my code why am I getting this error ?
You should not remove from a list while iterating it. Use, for instance, a list comprehension and slice assignment to achieve the same modification:
lst = [1,2,3,4,5,6]
lst[:] = [x for x in lst if x % 2 == 0]
# or simply (if you don't need to mutate the original list)
# lst = [x for x in lst if x % 2 == 0]
print(lst)
# [2, 4, 6]
This has also better time complexity (linear) whereas the repeated remove approach is quadratic.
Instead of removing the item from the original list, you can also split the original list into 2 new lists, evens and odds
lst=[1,2,3,4,5,6]
evens = []
odds = []
for i in lst):
if(i % 2 != 0):
odds.append(i)
else:
evens.append(i)
print(evens)
