I have the following:
const entries =
[
["mango", 2],
["orange", 3],
["strawberry", 0],
["banana", 10]
]
I would like to iterate over the arrays inside entries[], remove any arrays that have a 0 and have them going in descending order, so the above would change to:
newArr =
[
["banana", 10]
["orange", 3]
["mango", 2]
]
Thanks.
let entries =
[
["mango", 2],
["orange", 3],
["strawberry", 0],
["banana", 10]
]
entries = entries.filter(pr => pr[1] !== 0);
entries.sort((pr, nt) => nt[1] - pr[1])
It can be done through filter and sort:
const result = entries.filter(f => f[1] != 0).sort((a, b)=> b[1] - a[1]);
An example:
let entries =
[
["mango", 2],
["orange", 3],
["strawberry", 0],
["banana", 10]
];
const result = entries.filter(f => f[1] != 0).sort((a, b)=> b[1] - a[1]);
console.log(result)
const entries = [["mango", 2], ["orange", 3], ["strawberry", 0], ["banana", 10]]
function filterSort (arr) {
return entries
.filter(([, num]) => num > 0)
.sort(([, a], [, b]) => b - a)
}
console.log(filterSort(entries))Note that the entries array is not modified. No items were removed.
Use filter and sort methods with destructure.
const entries = [
["mango", 2],
["orange", 3],
["strawberry", 0],
["banana", 10]
];
const result = entries.filter(([,x]) => x).sort(([,a], [,b]) => b - a);
console.log(result);
filterandsort