I have a string like "portal100common2055".
I would like to split this into two parts, where the second part should only contain numbers.
"portal200511sbet104" would become "portal200511sbet", "104"
Can you please help me to achieve this?
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If you only want the last four characters why not substring?James Anderson– James Anderson2011-05-25 06:44:21 +00:00Commented May 25, 2011 at 6:44
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substring i can do but i dont know weather i can have only last 4 characters as numeric.it can be last 5 characters or 3 the below solution is working fine.Raja– Raja2011-05-25 07:04:27 +00:00Commented May 25, 2011 at 7:04
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2 Answers
Like this:
Matcher m = Pattern.compile("^(.*?)(\\d+)$").matcher(args[0]);
if( m.find() ) {
String prefix = m.group(1);
String digits = m.group(2);
System.out.println("Prefix is \""+prefix+"\"");
System.out.println("Trailing digits are \""+digits+"\"");
} else {
System.out.println("Does not match");
}
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String[] parts = input.split("(?<=\\D)(?=\\d+$)");
if (parts.length < 2) throw new IllegalArgumentException("Input does not end with numbers: " + input);
String head = parts[0];
String numericTail = parts[1];
This more elegant solution uses the look behind and look ahead features of regex.
Explanation:
(?<=\\D)means at the current point, ensure the preceding characters ends with a non-digit (a non-digit is expressed as\D)(?=\\d+$)means t the current point, ensure that only digits are found to the end of the input (a digit is expressed as\d)
This will only the true at the desired point you want to divide the input
Comments
