arrays value string edit and loop in combination with other array and looping

Question

for each Example 1 caption and some occurrences for the source map

What am I doing wrong?

Images Array

$imgsArray = array(
  'image1-small.jpg', 'image1-medium.jpg', 'image1-large.jpg',
  'image2-small.jpg', 'image2-medium.jpg', 'image2-large.jpg',
  'image3-small.jpg', 'image3-medium.jpg', 'image3-large.jpg'
); // sometimes more pictures too

Captions Array

$imgCaption = array('Adam','Peter'); // if e.g. with 3 pictures only 2 captions are available then I get Notice: Undefined offset:

the code

foreach($imgsArray as $files => $img) {
  // important! $first_char. delete from hyphen to the last string
  $first_char = substr($img,0,strpos($img,"-"));
  ///
  if ($first_char != $last_entry) {
  echo '<p>This is '.$imgCaption[$files];
  echo '<ul>';
    echo '<li>'.$first_char.'-small.jpg</li>';
    echo '<li>'.$first_char.'-medium.jpg</li>';
    echo '<li>'.$first_char.'-large.jpg</li>';
    echo '<li>'.$imgCaption[$files].'</li>';
  echo '</ul>';
  echo '<i>Ciao, '.$imgCaption[$files].'</i><br>---</p>';
  }
  $last_entry = $first_char;
}

unexpected

This is Adam

image1-small.jpg
image1-medium.jpg
image1-large.jpg
Adam

Ciao, Adam
---

This is Notice: Undefined offset: 3 in...

image2-small.jpg
image2-medium.jpg
image2-large.jpg
Notice: Undefined offset: 3 in...

Ciao, Notice: Undefined offset: 3 in...
---

This is Notice: Undefined offset: 3 in...
image3-small.jpg
image3-medium.jpg
image3-large.jpg
Notice: Undefined offset: 6 in...
Ciao, Notice: Undefined offset: 3 in...
---

expected

This is Adam

image1-small.jpg
image1-medium.jpg
image1-large.jpg
Adam

Ciao, Adam
---

This is Peter

image2-small.jpg
image2-medium.jpg
image2-large.jpg
Peter

Ciao, Peter
---

This is

image3-small.jpg
image3-medium.jpg
image3-large.jpg
Susi

Ciao,
---

Ajith · Accepted Answer · 2020-04-11 11:08:44Z

2

Can you try my below code

<?php
$imgsArray = array(
  'image1-small.jpg', 'image1-medium.jpg', 'image1-large.jpg',
  'image2-small.jpg', 'image2-medium.jpg', 'image2-large.jpg',
  'image3-small.jpg', 'image3-medium.jpg', 'image3-large.jpg'
);

$imgCaption = array('Adam','Peter','Susi');

$files = 0;

for( $i= 0; $i < count($imgsArray); $i=$i+3 ){
  if(!isset($imgCaption[$files])) break;
  $first_char = substr($imgsArray[$i],0,strpos($imgsArray[$i],"-"));

  echo '<p>This is '.$imgCaption[$files];
  echo '<ul>';
    echo '<li>'.$first_char.'-small.jpg</li>';
    echo '<li>'.$first_char.'-medium.jpg</li>';
    echo '<li>'.$first_char.'-large.jpg</li>';
    echo '<li>'.$imgCaption[$files].'</li>';
  echo '</ul>';
  echo '<i>Ciao, '.$imgCaption[$files].'</i><br>---</p>';

  $files++;
}

Demo link

edited Apr 11, 2020 at 11:08

answered Apr 11, 2020 at 10:28

Ajith

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7 Comments

Cem Firat Over a year ago

Thanks for the answer. But, what if the array quantities are not the same? e.g. $ imgCaption = array ('Adam', 'Peter'); Notice: Undefined offset: ...

Ajith Over a year ago

One question. your $imgsArray sequence will be always correct ? If so I ll alter my answer

Cem Firat Over a year ago

// sometimes more pictures too.

Ajith Over a year ago

I think 3 Images each of the 3 captions, Can you please elaborate, Question is bit confusing.. Need to find a combination in your question. I thought if caption is ('Adam', 'Peter'); Then only 6 values might be there in $imgsArray

Ajith Over a year ago

@CemFirat A checking inside for loop will solve the issue , please check this link 3v4l.org/75S4W

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