Javascript check if value exsist in two arrays return missing value

Question

I'd like to know IF a value is missing which one is missing.

Array1: You have these values at the moment

['cloud:user', 'cloud:admin']

Array2: You need to have these values in order to continue

['cloud:user', 'cloud:admin', 'organization:user']

Current method which returns true or false. But I'd like to know IF a value is missing which one is missing. For example: 'organization:user'. If nothing is missing return true.

let authorized = roles.every(role => currentResourcesResult.value.includes(role));

Does this answer your question? Simplest code for array intersection in javascript — A l w a y s S u n n y
– A l w a y s S u n n y, Commented Apr 10, 2020 at 12:51

StepUp · Accepted Answer · 2020-04-10 12:56:22Z

1

Just use filter method and check whether some of elements of arr1 is not equal to an element of an arr2:

const missingValues = arr2.filter(f => !arr1.some(s => s ==f));

An example:

let arr1 = ['cloud:user', 'cloud:admin']
let arr2 = ['cloud:user', 'cloud:admin', 'organization:user'];
const missingValues = arr2.filter(f => !arr1.some(s => s ==f));
console.log(missingValues);

edited Apr 10, 2020 at 12:56

answered Apr 10, 2020 at 12:50

StepUp

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Comments

Community · Accepted Answer · 2020-06-20 09:12:55Z

0

You can check it by using Array.prototye.filter().

const domain = ['cloud:user', 'cloud:admin', 'organization:user'];
const data = ['cloud:user', 'cloud:admin'];

const notInDomain = domain.filter(item => data.indexOf(item) === -1);

if (notInDomain.length > 0) {
  console.log('Some values are not in the domain set');
}

console.log(notInDomain);

Update

You can gain the same result by using includes instead of indexOf.

const notInDomain = domain.filter(item => !data.includes(item));

edited Jun 20, 2020 at 9:12

CommunityBot

11 silver badge

answered Apr 10, 2020 at 12:53

Sajeeb Ahamed

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