stdClass object array inside of another array

Question

I'm trying to get information from the $array1 below.

I'm getting with no problems venue's name and location address by doing:

$array2 = array();
$array3 = array();
foreach($array1 as $item){

                 $array2[] = $item->venue->name;
                 $array3[] = $item->venue->location->address;
}

But now I need to get the photos url and I don't know how to do it.

Thanks a million!

$array1:

Array
(
    [0] => stdClass Object
        (
               [venue] => stdClass Object

                (

                    [name] => a name
                    [location] => stdClass Object
                        (
                            [address] => main street

                        )


                )

            [photos] => stdClass Object
                (
                    [count] => 1
                    [items] => Array
                        (
                            [0] => stdClass Object
                                (

                                    [url] => http://folder/photo1.jpg

                    .
                    .
                    )))
.
.

Ondřej Mirtes · Accepted Answer · 2011-05-23 15:12:35Z

2

$array1[0]->photos->items[0]->url

Remember - you access arrays with [index] parenthesis, objects with -> arrows.

answered May 23, 2011 at 15:12

Ondřej Mirtes

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Comments

Sabeen Malik · Accepted Answer · 2011-05-23 15:13:14Z

1

Untested code:

$array2 = array();
$array3 = array();
$photos = array();
foreach($array1 as $item){
    $array2[] = $item->venue->name;
    $array3[] = $item->venue->location->address;

    $item_photo_urls = array();
    foreach($item->photos->items as $photo){
        $item_photo_urls[] = $photo->url;
    }

    $photos[] = $item_photo_urls;
}

Now you have a third array called photos , which contains all the photo urls.

answered May 23, 2011 at 15:13

Sabeen Malik

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1 Comment

Stephane Gosselin Over a year ago

You beat me to it + oned for the loop that checks for multiple images and not using $array4 as variable name ;o)

Rodolphe · Accepted Answer · 2011-05-23 15:12:19Z

0

Try this :

$url = $item->photos->items[0]->url;

answered May 23, 2011 at 15:12

Rodolphe

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