I have string
MATERIAL : 51670 TUD1 = .1200 m TLD1 = .0750 m TUD2 = .0620 m TLD2 = .0380 m TUDH = .0680 m TLDH = .0420 m
I only want to extract [51670, .1200, .0750, .0620, .0380, .0680, .0420]
I have tried re.findall("[-+]?\d*\.\d+|\d+", lines) but it returns [' 51670', '1', '.1200', '1', '.0750', '2', '.0620', '2', '.0380', '.0680', '.0420'] which is not what I want. Please help.
You may use
(?<!\w)[-+]?\d*\.?\d+(?!\d)
See the regex demo
Here, the pattern matches
(?<!\w) - a location in the string that is not immediately preceded with a word char (letter, digit or _). To allow _, replace (?<!\w) with (?<![^\W_])[-+]? - an optional - or +\d*\.?\d+ - 0+ digits, an optinal dot and 1+ digits(?!\d) - no digit allowed immediately to the right of the current location.See Python demo:
import re
text = "MATERIAL : 51670 TUD1 = .1200 m TLD1 = .0750 m TUD2 = .0620 m TLD2 = .0380 m TUDH = .0680 m TLDH = .0420 m"
print( re.findall(r'(?<!\w)[-+]?\d*\.?\d+(?!\d)', text) )
# => ['51670', '.1200', '.0750', '.0620', '.0380', '.0680', '.0420']
I would do:
import re
lines = 'MATERIAL : 51670 TUD1 = .1200 m TLD1 = .0750 m TUD2 = .0620 m TLD2 = .0380 m TUDH = .0680 m TLDH = .0420 m'
numbers = re.findall(r"\s(\.?\d+)\s",lines)
print(numbers)
Output:
['51670', '.1200', '.0750', '.0620', '.0380', '.0680', '.0420']
I simply look for 0 or 1 . (\.?) followed by 1 or more digits (\d+), which are between whitespaces (\s). I put \ses outside group so they will not appear in numbers. Note that above code will find all numbers from your example, but not numbers like 12.34 - to find them too use r"\s(\d+\.?\d+)\s". Note that . needs to be escaped as character with special meaning.
