How to loop through a string then find if a part of that string is in an arrayList

Question

What I am trying to do is to find loop through a string then match them with an arrayList.

Say, I got this code working:

import java.io.*;
import java.text.ParseException;
import java.util.*;

public class Test_Mark4 {
    public static ArrayList<String> patterntoSearch;
    public static void main(String[] args) throws IOException, ParseException {
        String text = "Lebron James";
        patterntoSearch = new ArrayList();
        patterntoSearch.add("Lebron James");
        patterntoSearch.add("Michael Jordan");
        patterntoSearch.add("Kobe Bryant");
        System.out.println(patterntoSearch);
        System.out.println(text);
        boolean valueContained = patterntoSearch.contains(text);
        System.out.println(valueContained);
    }
}

However, what if I replace String text = "Lebron James"; with String text = "Lebron James 2017-218 NBA Hoops Card";? Clearly there is the string Lebron James in that string, but it got mixed with other words as well (which I would not care, and only care about the string Lebron James. I have thought about a for loop but unsure how to construct it.

Andronicus · Accepted Answer · 2020-03-17 02:11:24Z

2

You can use regular expression for that:

patterntoSearch.stream()
    .anyMatch(s -> text.matches(".*" + s + ".*"));

This returns boolean indicating whether any element in patterntoSearch is contained in text.

patterntoSearch.stream()
    .filter(s -> text.matches(".*" + s + ".*"))
    .collect(Collectors.toList());

This will return a list of words in patterntoSearch, that are contained in text. If you want only one, then:

patterntoSearch.stream()
    .filter(s -> text.matches(".*" + s + ".*"))
    .findAny()
    .orElse(null);

I have passed null as default, but you can provide any String.

answered Mar 17, 2020 at 2:11

Andronicus

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