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How do I detect if a script is run from a Windows console or from Komodo debugger without passing different arguments to the script?

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  • have you inspected sys.argv ? Commented May 20, 2011 at 7:04
  • @Sentinel: I would prefer not to use args to distinguish. Commented May 20, 2011 at 7:10

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Although I don't know Komodo, I don't think its standard input is interactive, so you could try

import sys
in_console = sys.__stdin__.isatty()

in_console will then be true if the invoker provides interactive stdin and you will get what you want, though not in an elegant way.

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