Convert String to String() VB.NET

Question

Hello everyone I don't know how I can put the values I get from the list into String() format.

This is my current code:

 Private files As String()
files = New String() {
            "00", "01", "02", "03", "04", "05", "06", "07",
            "08", "09", "0A", "0B", "0C", "0D", "0E", "0F",
            "10", "11", "12", "13", "14", "15", "16", "17",
            "18", "19", "1A", "1B", "1C", "1D", "1E", "1F",
            "20", "21", "22", "23", "24", "25", "26", "27",
            "28", "29", "2A", "2B", "2C", "2D", "2E", "2F",
            "30", "31"}

Dim vals As New List(Of String)()
        Dim Counter As Integer
        For Counter = 1 To 5
            vals.Add(Counter.ToString)
        Next

        files = String.Join(",", vals) 'I'm getting an error here that I can't convert String to String ()

I want to finally bob this result: files = new String() {"1","2","3","4","5"}

Thank you all for your help

String.Join returns a String. vals is already a List(Of String). Maybe you want .ToArray(). Or what do you want? — mm8
– mm8, Commented Feb 21, 2020 at 13:32
@mm8 yes it is clear to me that String.Join returns a string, how can I return ToArray()? — Mara
– Mara, Commented Feb 21, 2020 at 13:34
@mm8 I have a values values Counter.Tostring(), is it possible for this part to take values in a string? LIKE: files = Enumerable.Range(1.tostring(), 5.tostring()).toArray() — Mara
– Mara, Commented Feb 21, 2020 at 13:41
I am not sure I follow. Enumerable.Range accepts two Integers. It doesn't accept strings. — mm8
– mm8, Commented Feb 21, 2020 at 13:45
@mm8 so yes i'm clear but with me the files string () as I stated in the question and in your answer is files = integer — Mara
– Mara, Commented Feb 21, 2020 at 13:46

mm8 · Accepted Answer · 2020-02-21 13:50:09Z

2

String.Join returns a String. vals is already a List(Of String)...

If you want a String(), you can just convert the list to an array:

files = vals.ToArray()

...or avoid creating the list in the first place:

files = Enumerable.Range(1, 5).Select(Function(x) x.ToString).ToArray()

edited Feb 21, 2020 at 13:50

answered Feb 21, 2020 at 13:36

mm8

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1 Comment

djv Over a year ago

@Mara You can also do a similar thing with that hex array Dim files = Enumerable.Range(0, 50).Select(Function(x) x.ToString("X2")).ToArray()

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