how to make a new array from an existing array in php?

Question

let's say if I have an array like this below.

$i = array(
    'arr1'  => array(
        'a11'   => 'ar11',
        'a12'   => 'ar12',
    ),
    'arr2'  => array(
        'a21'   => 'ar21',
        'a22'   => 'ar22',
        'a23'   => 'ar23',
    ),
    'arr3'  => 'arrr3',
    'arr4'  => 'arrr4'
);

I want a new array that created from this array like the one I mentioned below,

$j = array(
    'a11'   => 'ar11',
    'a12'   => 'ar12',
    'a21'   => 'ar21',
    'a22'   => 'ar22',
    'a23'   => 'ar23',
    'arr3'  => 'arrr3',
    'arr4'  => 'arrr4'
);

sofar I tried extracting the last two elements which aren't arrays I mention the code below

$ii = $i;
foreach($ii as $k => $v):
    if(is_array($v)):
        unset($ii[$k]);
    endif;
endforeach;

this returns me the last two elements. but the way i tried extracting the other elements looks wired see below.

$i1 = $i['arr1'];
$i2 = $i['arr2'];
$i3 = array_merge($i1, $i2);
$final = array_merge($i3, $j);

this looks simple because it has small amout of elemetns but i have large amount of elements in my project, any other ways to get this output?

webprogrammer · Accepted Answer · 2020-02-15 10:47:59Z

1

Can you try this?

$final = [];

foreach($i as $key => $value){
    if(is_array($value){
        $final = array_merge($final, $value);

    }   else{
        $final[$key] = $value;
    }
}

Upd.

@Magnus-Eriksson insists to explain what is going on within loop. At first we check if value is an array or not. If value is an array we merge nested array with (new, created before loop starts) array where we putting our elements. If value isn't array we just get that value and add it to the final array. There is no magic here. But answer with array_walk_recursive() below is much more elegant but with "magic" within.

edited Feb 15, 2020 at 10:47

answered Feb 15, 2020 at 10:17

webprogrammer

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2 Comments

M. Eriksson Over a year ago

Instead of just posting a code snippet, tailored to the OP's issue, you should also include a proper explanation of what it solves and how. If not, the question won't be particularly helpful for future visitors.

M. Eriksson Over a year ago

Waiting for the author to comment what? Your code either solves the OP's issue or it doesn't. They have shown us the expected result so you should know if it does.

Olivier · Accepted Answer · 2020-02-15 10:28:40Z

1

array_walk_recursive() is what you need:

$a = array(
    'arr1'=> array(
        'a11' => 'ar11',
        'a12' => 'ar12',
    ),
    'arr2'=> array(
        'a21' => 'ar21',
        'a22' => 'ar22',
        'a23' => 'ar23',
    ),
    'arr3' => 'arrr3',
    'arr4' => 'arrr4'
);

$b = array();
array_walk_recursive($a, function($val, $key) use(&$b)
{
    $b[$key] = $val;
});

You can test it here.

edited Feb 15, 2020 at 10:28

answered Feb 15, 2020 at 10:22

Olivier

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4 Comments

Vigneshwaran Over a year ago

it works, but I don't know what's happening inside your code even after I read the docs about array_walk_recurssive function.

Olivier Over a year ago

Basically array_walk_recursive() visits all the elements contained in $a that are simple values (i.e. not arrays).

Vigneshwaran Over a year ago

hmm, but how did you apply the condition? what is that use(&$b) means?

Olivier Over a year ago

The use keyword allows a closure to capture a variable. See this and that for more informations.

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