How can I encode an array into json with additional data?

Question

I am creating a json file from my array:

$file = json_encode($array);

The json file will look like this:

     [
      {
          "name": "file1.html",
          "date": "2019-01-29T20:33:57.000163Z",
          "size": "348"
      }
      {
          "name": "file2.xml",
          "date": "2019-01-29T20:33:57.000167Z",
          "size": "401"
      }
      {
          "name": "file3.html",
          "date": "2019-01-29T20:33:57.000171Z",
          "size": "1314"
      }
   ]

But I need to create a json file with some little bit different format. The output I need is:

{ 
 "draw": 1,
 "recordsTotal": 5000,
 "recordsFiltered": 5000,
 "data": [
      {
          "name": "file1.html",
          "date": "2019-01-29T20:33:57.000163Z",
          "size": "348"
      }
      {
          "name": "file2.xml",
          "date": "2019-01-29T20:33:57.000167Z",
          "size": "401"
      }
      {
          "name": "file3.html",
          "date": "2019-01-29T20:33:57.000171Z",
          "size": "1314"
      }
   ]
}

Is this possible with json_encode?

Where do the other values come from?

Nick
– Nick

2020-02-11 12:46:19 +00:00
Commented Feb 11, 2020 at 12:46 — Nick
– Nick, Commented Feb 11, 2020 at 12:46
@Nick I need to add them manually

peace_love
– peace_love

2020-02-11 12:47:31 +00:00
Commented Feb 11, 2020 at 12:47 — peace_love
– peace_love, Commented Feb 11, 2020 at 12:47

Death-is-the-real-truth · Accepted Answer · 2020-02-11 12:47:33Z

4

Create a new array with rest of the info and assign current array data into it as well.

$newArray = array(
    'draw'=> 1,
    'recordsTotal'=> 5000,
    'recordsFiltered'=> 5000,
    'data'=>$array
);

$file = json_encode($newArray);

answered Feb 11, 2020 at 12:47

Death-is-the-real-truth

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