call a function using variable in function name

Question

foreach($arr as $el){
    $what= $el->what;
    if($what == 'img'){get_img();}
    elseif($what == 'video'){get_video();
    elseif($what == 'something'){get_something();} 
}

How to say the above shortly, like this:

 get_$what();

Jan Myszkier · Accepted Answer · 2020-02-07 19:37:55Z

2

as in https://www.php.net/manual/en/functions.variable-functions.php

$func = 'foo';
$func();        // This calls foo()

so in your case:

foreach($arr as $el){
    $what= $el->what;
    $funcname = 'get_'.$what;
    $funcname();
}

answered Feb 7, 2020 at 19:37

Jan Myszkier

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Comments

Dharman · Accepted Answer · 2020-02-07 19:55:20Z

2

You can use parentheses

<?php

function ab(){echo 'ho';}
$foo='video';
('get_'.$foo)();

edited Feb 7, 2020 at 19:55

answered Feb 7, 2020 at 19:47

Dharman♦

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1 Comment

Dharman Over a year ago

I already answered this question once. If I could only find where.

Nicolas · Accepted Answer · 2020-02-07 19:38:58Z

1

You could save the function name into a variable and then call that function dynamically by adding () to the variable. ( not sure if i said this right )

$yourFunction = 'get_';
$yourFunction .= 'img';

$value = $yourFunction();
// will execute get_img();

here is a fiddle to play with

answered Feb 7, 2020 at 19:38

Nicolas

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Comments

Sadak · Accepted Answer · 2020-02-07 19:50:16Z

1

 function get_id(){
        echo "id";
       }
    function get_d(){
        echo "d";
        }

      $id='id';
      $fun='get_'.$id;
      $fun();

outputs: id

answered Feb 7, 2020 at 19:50

Sadak

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