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Something magical happen. I'm stuck. How to push string into array?

const createParamForm = (paramsForms, setParamsForms) => {
  console.log('TCL: createParamForm -> paramsForms', paramsForms)
  const id = `f${(+new Date()).toString(16)}`
  console.log('TCL: createParamForm -> id', id)
  const paramsFormsClone = cloneDeep(paramsForms)
  console.log('TCL: createParamForm -> paramsFormsClone', paramsFormsClone)
  console.log(paramsFormsClone.push('banan'))
  // setParamsForms(newParamsForms)
}

The logs:

enter image description here

Why i'm getting 1 instead of ['banan'] ??

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4 Answers 4

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2

Array push returns the new length of the array, not the actual values in it. Your'e fine.

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1

Issue: Instead of logging paramsFormsClone, you have been logged operation paramsFormsClone.push('banan') which returns the new length of the array(1 here).

You have to change the code as:

const createParamForm = (paramsForms, setParamsForms) => {
  console.log('TCL: createParamForm -> paramsForms', paramsForms)
  const id = `f${(+new Date()).toString(16)}`
  console.log('TCL: createParamForm -> id', id)
  const paramsFormsClone = cloneDeep(paramsForms)
  console.log('TCL: createParamForm -> paramsFormsClone', paramsFormsClone)
  paramsFormsClone.push('banan')
  console.log(paramsFormsClone)
  // setParamsForms(newParamsForms)
}
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Comments

1

console.log(paramsFormsClone.push('banan')); statement return length of array.

Please check by using console.log(paramsFormsClone);

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1

As push() returns the new length of the array after changes hence in your case it returns 1.

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