trouble using lambda in python

Question

I am trying to write a lambda where it takes the minutes and divides it by a range, then prints out the result. I tried

       list((lambda minutes: minutes / range),range(Numbe+1,1))

but list only takes one argument, any ideas? Minutes and Number the user supplies

I figured it out using

        List=[]
        List=range(1, Number+1)
        List.reverse()
        print(List)
        for number in List:
            print ( minutes/ number)

I know that the code look very novice and would appreciate any tips to get is to look better

This is just a style issue, but you've fallen into the same trap as many beginners. Describe your problem, don't ask how to do what you've decided is the solution :) — richo
– richo, Commented May 10, 2011 at 3:33

John La Rooy · Accepted Answer · 2011-05-10 03:20:10Z

4

Do you really need to use a lambda? Here is a list comprehension which most people seem to find easier to read

[float(minutes)/number for minutes in range(1,number+1)]

The equivalent using a lambda function is

 map(lambda minutes: float(minutes)/number, range(1,number+1))

And a shorter way to write that is

map(float(number).__rdiv__, range(1,number+1))

The float function is needed here (unless you are using Python3) because otherwise an integer division is done

answered May 10, 2011 at 3:20

John La Rooy

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1 Comment

riza Over a year ago

Instead of using the float function, op can also set "from _ future _ import division".

Senthil Kumaran · Accepted Answer · 2011-05-10 03:25:19Z

0

What you are looking for is map built-in function, which acts upon individual elements of the container passed to it as the second argument and returns the result which is a list. The first argument is many a times a lambda which takes the argument and acts upon it. In your case, the minutes and number.

map(lambda number:number/rangeval,range(1,rangeval))

answered May 10, 2011 at 3:25

Senthil Kumaran

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