Using scanf to get user inputs for dynamic arrays in c

Question

When I try to get user input for the dynamic array, it stops at the first for loop. It gives me an error that my program has stopped working. Help me out!

#include<stdio.h>
#include<stdlib.h>

int main(){
    int count = 0, sum = 0, *number = NULL, index = 0, size = 0;
    scanf("%d", &size);

    number = (int *)calloc(size, sizeof(int)); //Dynamic allocation

    printf("Enter the elements\n");
    for(index = 0; index < size; index++){
        scanf("%d",number[index]); //Getting the input values from user but i get an error
    }
    return 0;
}

int *number; .... scanf("%d",number[index]); Save time. Enable compiler warnings, Faster feedback the posting on SO. — chux
– chux, Commented Dec 14, 2019 at 8:16
Generally scanf is not a good idea. See what-can-i-use-for-input-conversion-instead-of-scanf for lots of information on this. Using fgets in combination with sscanf is already a big improvement. — hko
– hko, Commented Dec 16, 2019 at 17:11

kiner_shah · Accepted Answer · 2019-12-14 04:09:20Z

2

Use this instead:

scanf("%d", &number[index]);

Note the & operator before number[index] is needed when using scanf for integer input.

answered Dec 14, 2019 at 4:09

kiner_shah

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