How to dynamically loop through an arraylist and add each nth element

Question

I have been given a list of data points that I have added into an arraylist of arraylist. The challenege I am now facing is that I must add every nth element by dim in this case 4 -1 =3 elements. Therefore I need to add element 0 + 3, 1 + 4 and 2 + 5.

Here is the view of the arraylist of arraylife

[[-0.2499999999998725, 0.09887005649714048, 0.12499999999997119, 0.2499999999998725, 0.34887005649701297, 0.3749999999998437, -0.09887005649714048, -0.34887005649701297, 0.02612994350283071, -0.12499999999997119, -0.3749999999998437, -0.02612994350283071],
[0.027777777777828083, -0.2504708097928492, -0.2638888888887171, -0.027777777777828083, -0.2782485875706773, -0.29166666666654517, 0.2504708097928492, 0.2782485875706773, -0.013418079095867896, 0.2638888888887171, 0.29166666666654517, 0.013418079095867896], 
[-0.40277777777757906, 0.15442561205268038, 0.1805555555555111, 0.40277777777757906, 0.5572033898302594, 0.5833333333330901, -0.15442561205268038, -0.5572033898302594, 0.02612994350283071, -0.1805555555555111, -0.5833333333330901, -0.02612994350283071]]

for(int i = 0; i < ai.size(); i++) {
    for(int k = 0; k < ai.get(i).size(); k++) {
        System.out.println(k +"   " + ai.get(i).get(k));
        }
    System.out.println("BREAK");
    }

Here you can see I added every third element. So its 0 + 3 + 6 + 9, 1 + 4 + 7 + 10 and 3 + 5 + 8 + 11. The expect output should be a single number Expect output

[[-0.22387005649, -0.2761299435, 0.5][arraylist two answer][ arraylist three answer]]

When I use k += 3 it only gets 0 + 3 + 6 + 9 then it breaks and goes into the next arraylist. It never gets 1 + 4 + 7 + 10 and 3 + 5 + 8 + 11 — Anta
– Anta, Commented Nov 16, 2019 at 14:39
@dasblinkenlight Sample input/output implies each sub-array is 3N long and should be filtered into 3 sums [sum(k%3==0), sum(k%3==1), sum(k%3==2)] — drekbour
– drekbour, Commented Nov 16, 2019 at 14:42

drekbour · Accepted Answer · 2019-11-16 14:58:09Z

1

You need three sums:

    for(List<Double> subList: ai) {
      int k = 0;
      double[] sums = {0d, 0d, 0d};
      for(Double d: subList) {
        sums[k++ % 3] += d; // Redirect d into one of three sums
      }
      List<Double> sumsAsList = Arrays.stream(sums).boxed().collect(Collectors.toList());
    }

answered Nov 16, 2019 at 14:58

drekbour

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