How to create a Json from object and variables?

Question

I have an object class that has the following variables:

class empleado
{
    public string nombre = "Nicolas";
    public string apellido = "Flores";
    public int edad= 22;
}

And I can generate a Json with this line of code:

string jsonResult = JsonConvert.SerializeObject(empleado);

But to the json that generates I would like to add other data apart from the object, how could I do it?

You don't want to add new properties to your empleado class, do you? — cxↄ
– cxↄ, Commented Nov 12, 2019 at 2:04
Use properties or addorn those fields with JsonPropoerty attribute — Nkosi
– Nkosi, Commented Nov 12, 2019 at 2:05
@Yeheshuah Yes, I don't want to add more properties because I want to show list of employee objects and then add some attributes or messages to that JSON — Nicolas Flores Muñoz
– Nicolas Flores Muñoz, Commented Nov 12, 2019 at 2:10

Thilina Koggalage · Accepted Answer · 2019-11-12 02:24:20Z

4

As another approach, you can keep a separate model like this. So you can assign your empleado object and other properties you want to it and then convert it to a Json object.

class MyJsonObjectModel
{
    public string otherProperty1 = "My string 1";
    public string otherProperty2 = "My string 2";
    public int otherProperty3 = "1";

    public empleado empleadoModel;
}

string jsonResult = JsonConvert.SerializeObject(MyJsonObjectModel);

edited Nov 12, 2019 at 2:24

answered Nov 12, 2019 at 2:16

Thilina Koggalage

1,0848 silver badges16 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

tmaj Over a year ago

BTW. This uses Json.NET, but for the record, as of .NET Core 3.0 System.Text.Json.JsonSerializer does not serialise fields (as opposed to properties)

tmaj · Accepted Answer · 2019-11-12 02:10:02Z

2

You cam use a anonymous type.

var o = new {
 P1 = "X",
 P2 = 2,
 empleado.nombre,
 empleado.apellido,
 empleado.edad
};

string jsonResult = JsonConvert.SerializeObject (o);

or

var o = new {
P1 = "X",
P2 = 2,
Emp = empleado
};

string jsonResult = JsonConvert.SerializeObject (o);

answered Nov 12, 2019 at 2:10

tmaj

35.9k12 gold badges108 silver badges143 bronze badges

1 Comment

tmaj Over a year ago

BTW. This uses Json.NET, but for the record, as of .NET Core 3.0 System.Text.Json.JsonSerializer does not serialise fields (as opposed to properties)

HazardousGlitch · Accepted Answer · 2019-11-12 02:10:25Z

The two methods I prefer are:

1) Create a new class in the same file as your serialization (or wherever you want but I like to keep custom items like that in the same file as the requesting code unless it's reusable) that has all the fields from empleado and add whatever other fields to it you need. For example:

class customempleado
{
    public string nombre = "Nicolas";
    public string apellido = "Flores";
    public int edad= 22;
    public string moredata1 = "More data 1";
    public string moredata2 = "More data 2";
}

2) Serialize a anonymous object and add the class and new data to it. For example:

string jsonResult = JsonConvert.SerializeObject ( new { nombre = "Nicolas", apellido = "Flores", edad = 22, moredata1 = "More data", moredata2 = moredata2 });

Nick Henry · Accepted Answer · 2019-11-12 02:45:41Z

Here's one way of performing all CRUD type operations on a de-serialized JSON object:

public static void ManipulateJsonObject()
{

    string json =
    @"{
        ""empleado"": {
            ""nombre"": ""My nombre"",
            ""apellido"": ""My apellido"",
            ""edad"": 1
        }
    }";

    JObject baseJObject = JObject.Parse(json);


    System.Diagnostics.Trace.WriteLine("JObject before modifications, just after parse:");
    System.Diagnostics.Trace.WriteLine(baseJObject.ToString());

    // Get node with name 'empleado'
    JObject empleadoNode = (JObject)baseJObject["empleado"];

    // Create new property 'afterNombre'
    empleadoNode.Property("nombre").AddAfterSelf(new JProperty("afterNombre", "new nombre value"));

    System.Diagnostics.Trace.WriteLine("Observe newly added property 'afterNobre':");
    System.Diagnostics.Trace.WriteLine(baseJObject.ToString());

    // Read value of new property 'afterNombre'
    string empleadoValue = (string) empleadoNode["afterNombre"];

    // Throws exception if value was not set
    if(string.IsNullOrWhiteSpace(empleadoValue))
        throw new Exception("Adding or Reading new property failed");

    // Update value of existing property 'edad'
    empleadoNode["edad"] = 3;

    System.Diagnostics.Trace.WriteLine("Observe newly property 'edad' has been updated:");
    System.Diagnostics.Trace.WriteLine(baseJObject.ToString());

    // Delete newly added property 'afterNombre'
    empleadoNode.Property("afterNombre").Remove();

    System.Diagnostics.Trace.WriteLine("Observe property 'afterNobre' has been deleted:");
    System.Diagnostics.Trace.WriteLine(baseJObject.ToString());
    // Output final object

    System.Diagnostics.Trace.WriteLine("Final state of JObject:");
    System.Diagnostics.Trace.WriteLine(baseJObject.ToString());
}

See visual studio Output window for inspection result after each manipulation.

Collectives™ on Stack Overflow

How to create a Json from object and variables?

4 Answers 4

1 Comment

1 Comment

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

1 Comment

1 Comment

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related