I am looking for a lookup function for print corresponding names. I have a list file
a Chief manager
b Assistant general manager
c general manager
D CTO
E CEO
I have a variable “user” in my script I want to check the variable in first column, if the value match then print corresponding name
Eg if “user”==a then print “Chief manager”
Using a dictionary will be easier.
d = { 'a': 'Chief Manager', 'b': 'Assistant General Manager', 'c': 'General Manager', 'D': 'CTO', 'E': 'CEO' }
user = 'a'
print(d[user])
# Chief Manager
To load that file into a dictionary, you could do this:
with open('/path/to/my/file') as myFile:
d = dict(line.strip().split(None, 1) for line in myFile)
print(d['a'])
# Cheif manager
If you want to parse a CSV file, it depends on how the file is actually formatted. If it looked like this:
a,"Cheif manager" b,"Assistant general manager" c,"general manager" D,"CTO" E,"CEO"
You could read that in like this:
from csv import reader
d = dict(row for row in reader(open('/path/to/my/file'), delimiter=',', quotechar='"'))
print(d['a'])
# Cheif manager
csv module can make parsing and creating the dictionary relatively easy.Assuming that the first column would be unique in someway, your first task would be to construct a dictonary with keys from the first column and values from the second.
to construct the dictionary, try it in the following manner.
org_dict = dict()
line = 'a Chief manager'
key,value = line.split(None,1)
org_dict[key] = value
Now to get each line from your file, you can open the file and read then line by line.
with open('myfile') as f:
for line in f:
# process your line
fields = line.split(None, 1) to split the line into the letter and the complete name.