i have an array like [x/0/2 , x/0/3 , y/3/1 , x/1/1 , x/0/3 , x/1/2],
i need to convert the elements range like [x/0/2-3 , y/3/1 , x/1/1-2] Please give some suggestion for this.
2 Answers
Use reduce to iterate over the array and create an object grouped by the element root, then use Object.entries to pull out the correct information from the object.
const arr = ['x/0/2', 'x/0/3', 'y/3/1', 'x/1/1', 'x/0/3', 'x/1/2'];
const out = arr.reduce((acc, c) => {
// `split` out the separate parts of the element
const [ root1, root2, index ] = c.split('/');
// We'll use the first two parts as the object key
const key = `${root1}/${root2}`;
// If the key doesn't already exist create an empty
// array as its values
acc[key] = acc[key] || [];
// To prevent duplicates only add an index if it
// isn't already in the array
if (!acc[key].includes(index)) acc[key].push(index);
// Return the accumulator for the next iteration
return acc;
}, {});
// Then iterate over the object entries with `map`
const result = Object.entries(out).map(([ key, values ]) => {
// Return the joined up value
return `${key}/${values.join('-')}`;
});
console.log(result);
2 Comments
Mohan
Thank you so much for support andy. But expectations is, If suppose my array is['x/0/2', 'x/0/3', 'y/3/4','y/3/9','x/1/1', 'x/1/2'] answer getting like ["x/0/2-3", "y/3/4-9", "x/1/1-2"] as per your code, but in this we don't have 'y/3/5','y/3/6','y/3/7','y/3/8' values range. the output should be ["x/0/2-3", "y/3/4","y/3/9", "x/1/1-2"] like this.
Andy
I could only create output based on the input you provided in your question. I have no idea what that other range of inputs does.
If I understand your question, you could create an array within the array to hold the range of values. Checking if the position in the array is an actual array let’s you know there are values that span a range within.
Example:
var values = [x/01, [x/20, x/21, x/22], x/03]
You could also create an object that could accomplish something similar depending on your needs.
x/0/2, etc.?