Doing hex in python to a full byte

Question

Is there a way to get python to print an even number of bytes when formatting hex? For example:

>>> hex(12)
'0xc'
>>> f'{12:#x}'
'0xc'
>>> f'{12:#X}'
'0XC'
>>> f'{12:X}'
'C'
>>> f'{12:x}'
'c'

Additionally, does python have a formatted that will separate bytes when there are multiple? For example:

>>> hex(1000)
'0x3e8' # 0e e8

Or would I need to create my own formatter for this?

John S · Accepted Answer · 2019-10-26 06:56:55Z

1

You can format fixed length hex values in a string using a format specifier...

like this:

 '{:04x}'.format(12)

Which returns:

'000c'

AFAIK you'll need to have a custom format function to group by position. Maybe something like this:

hex_value = '0123456789abcdef'
' '.join(hex_value[i: i + 2] for i in range(0, len(hex_value), 2))

Which will return:

'01 23 45 67 89 ab cd ef'

answered Oct 26, 2019 at 6:48

John S

4964 silver badges11 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1