PHP process $_POST array

Question

Following form has repeating input fields. Each field has two hidden inputs and one text input. I want to retrieve the values of each field when posted, so that I can store in the database.

<form action="" method="post">

    <?php
        $arr = [30, 40, 55];        
        foreach ($arr as $code) { ?>
            <?php 
                for ($i = 1; $i <= 12; $i++ ) { ?>
                    <input type="hidden" name="field[code]" value="<?php echo $code; ?>">
                    <input type="hidden" name="field[month]" value="<?php echo $i; ?>">
                    <input type="text" name="field[amount]"><?php 
                } 
        }
    ?>

    <button name="submit">Submit</button>

</form>

I can't figure out how to run the loop to retrieve all three values of each field. I'm trying the following:

<?php
    if( isset( $_POST['submit']) ){

        foreach( $_POST['field'] as $field ) { //<- problem
            $code = $field['code'];
            $month = $field['month'];
            $amount = $field['amount'];

            //insert into db
        } 

    }
?>

step 1) var_dump $_POST - see what's actually passed

treyBake
– treyBake

2019-10-18 09:07:28 +00:00
Commented Oct 18, 2019 at 9:07 — treyBake
– treyBake, Commented Oct 18, 2019 at 9:07

Areg · Accepted Answer · 2019-10-18 09:20:52Z

1

Assign a number foreach input field.

<?php
       $arr = [30, 40, 55];
       foreach ($arr as $code) { ?>
           <?php
               for ($i = 1; $i <= 12; $i++ ) { ?>
                   <input type="hidden" name="field[<?php echo $i ?>][code]" value="<?php echo $code; ?>">
                   <input type="hidden" name="field[<?php echo $i ?>][month]" value="<?php echo $i; ?>">
                   <input type="text" name="field[<?php echo $i ?>][amount]"><?php
               }
       }

   ?>

On the back-end

<?php
    if( isset( $_POST['submit']) ){
        foreach( $_POST['field'] as $key => $field ) { 
            $code = $field['code'];
            $month = $field['month'];
            $amount = $field['amount'];
            //insert into db
        }

    }
?>

answered Oct 18, 2019 at 9:20

Areg

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Comments

arkascha · Accepted Answer · 2019-10-18 09:11:53Z

1

This probably is what you are looking for:

<?php
// ...
if (isset( $_POST['submit']) && array_key_exists('field', $_POST)) {

    $code = $_POST['field']['code'];
    $month = $_POST['field']['month'];
    $amount = $_POST['field']['amount'];

    //insert into db
}

Or if you consider this easier to read:

<?php
// ...
if (isset( $_POST['submit']) && array_key_exists('field', $_POST)) {

    $field = &$_POST['field'];
    $code = $field['code'];
    $month = $field['month'];
    $amount = $field['amount'];

    //insert into db
}

answered Oct 18, 2019 at 9:11

arkascha

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Comments

LuisH · Accepted Answer · 2019-10-18 09:14:29Z

1

<form action="" method="post">

    <?php
        $arr = [30, 40, 55];        
        foreach ($arr as $code) { ?>
            <?php 
                for ($i = 1; $i <= 12; $i++ ) { ?>
                    <input type="hidden" name="field[code][]" value="<?php echo $code; ?>">
                    <input type="hidden" name="field[month][]" value="<?php echo $i; ?>">
                    <input type="text" name="field[amount][]"><?php 
                } 
        }
    ?>

    <button name="submit">Submit</button>

</form>

then,dump($_POST);

answered Oct 18, 2019 at 9:14

LuisH

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