how to return fail if numpy array is not specified values

Question

I would like the code to return "fail" statement if the numpy array contains value that is not 0 or 10. Checking 2nd and 3rd column, as long as there is one value that doesn't satisfy the criteria, the code returns "fail". My code always return pass.

data file has the format:

data = np.loadtxt('datafile.txt')
x1, x2 = data[:,1], data[:2]

if (x1.any != 0 or x1.any !=10):
    x1label = 'fail'
else:
    x1label = 'pass'

if (x2.any !=0 or x2.any !=10):
    x2label = 'fail'
else:
    x2label = 'pass'

if (x1label == 'fail') or (x2label == 'fail'):
    label = 'fail'
else:
    label = 'pass'

Manualmsdos · Accepted Answer · 2019-10-17 05:28:34Z

1

You use any before comparison, which mean you compare bool with int.

data = np.loadtxt('datafile.txt')
x1, x2 = data[:,1], data[:2]

if np.any(x1 != 0) or np.any(x1 !=10):
    x1label = 'fail'
else:
    x1label = 'pass'

if np.any(x2 !=0) or np.any(x2 !=10):
    x2label = 'fail'
else:
    x2label = 'pass'

if (x1label == 'fail') or (x2label == 'fail'):
    label = 'fail'
else:
    label = 'pass'

edited Oct 17, 2019 at 5:28

answered Oct 17, 2019 at 5:21

Manualmsdos

1,5473 gold badges16 silver badges25 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

hamster Over a year ago

If i don't use any, it gets the following error ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

Manualmsdos Over a year ago

@hamster you can use np.any, why not.

hamster Over a year ago

Ah. My mistake. I didn't see you have moved any before the comparison. It is now returning fail which is correct. But when i put into a loop, reading the second file, which should have given me "pass" , it isn't.

hamster Over a year ago

Instead of just 'datafile.txt', i now put it in a loop to read in several data files one-by-one and do the same evaluation. I am expecting the first to return fail, and the second to return pass. I am not sure how to write an example code under comment.

hamster Over a year ago

I think i know why doing the loop doesn't work. As a test, i change "50" in the data file to "10", your code should have returned "pass" but it isn't.

hamster · Accepted Answer · 2019-10-17 09:09:05Z

0

A different approach, which i find it works.

    import numpy as np

    a_file = open('datafile.txt', 'r')
    LINES = a_file.readlines()
    a_file.close()

    for i in range(len(LINES)):
        line = LINES[i]
        TOKS = line.split()
        x1 = TOKS[1]
        x2 = TOKS[2]
        if (x1 != '0' and x1 != '10'):
            x1label = 'fail'
            break        
        else:
            x1label = 'pass'

        if (x2 != '0' and x2 != '10'):
            x2label = 'fail'
            break        
        else:
            x2label = 'pass'

    if (x1label == 'fail') or (x2label == 'fail'):
            label = 'fail'
    else:
            label = 'pass'

answered Oct 17, 2019 at 9:09

hamster

697 bronze badges

Collectives™ on Stack Overflow

how to return fail if numpy array is not specified values

2 Answers 2

5 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

5 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related