$a = array('a','b','c','d','e','f');
$b = array('1','2');
$count = 0;
$d = 0 ;
$input = array('ina', 'inb','inc');
foreach ($a as $key => $v) {
$count++;
echo $v;
echo $input[$key];
if ($count%3 == 0){
echo $b[$d++];
reset($input);
}
}
I want like this output
1
a-ina
b-inb
c-inc
2
d-ina
e-inb
f-inc
Actually I want $input two times in a foreach loop. $a have 6 items $input have 3 items and $b have 2 items. I need
To make it more applicable, Demo
$a = array('a','b','c','d','e','f');
$input = array('ina', 'inb','inc');
$loop = 1;
$input_length = count($input); // TODO process the length with 0 case.
foreach($a as $index => $value){
if(!($i = $index % $input_length)){
echo $loop . PHP_EOL;
$loop++;
}
echo $value . "_" . $input[$i] . PHP_EOL;
}
$b rather than your $loop counter.You're keeping a few variables that you don't really need as they can be derived from the $key value from $a. To get the output you want, you could do this:
$a = array('a','b','c','d','e','f');
$b = array('1','2');
$input = array('ina', 'inb','inc');
$len = count($input);
foreach ($a as $key => $v) {
$idx = $key % $len;
if ($idx == 0){
echo $b[floor($key/3)] . PHP_EOL;
}
echo $v . "-";
echo $input[$idx] . PHP_EOL;
}
Output:
1
a-ina
b-inb
c-inc
2
d-ina
e-inb
f-inc
