PhpStorm doesn't open files via xdebug.file_link_format

Question

PhpStorm doesn't open files via xdebug.file_link_format.

I tried different formats, and still doesn't work. I open link in new tab and nothing happens. Path is writing correct in address bar

xdebug.file_link_format = "phpstorm://open?file=%f&line=%l"

It was working. Maybe because my disk name is BOOTCAMP (C:\). Or phpstorm not in PATH? Or PhpStorm removed this feature? — Alexander Myravjev
– Alexander Myravjev, Commented Oct 14, 2019 at 17:50
Can I create my custom protocol for phpstorm, what can open file and line? — Alexander Myravjev
– Alexander Myravjev, Commented Oct 14, 2019 at 21:14
It's only supported for macOS out-of-the-box, for Windows, you need a 3rd party solution: github.com/aik099/PhpStormProtocol youtrack.jetbrains.com/issue/IDEA-65879 — Eugene Morozov
– Eugene Morozov, Commented Oct 17, 2019 at 9:58

Alexander Myravjev · Accepted Answer · 2019-10-17 13:32:32Z

1

I created my own protocol and custom program to open file in phpstorm

myproto.reg:

Windows Registry Editor Version 5.00

[HKEY_CURRENT_USER\Software\Classes\myproto]
@="phpstorm"
"URL Protocol"=""

[HKEY_CURRENT_USER\Software\Classes\myproto\shell]

[HKEY_CURRENT_USER\Software\Classes\myproto\shell\open]

[HKEY_CURRENT_USER\Software\Classes\myproto\shell\open\command]
@="\"C:\\Program Files\\nodejs\\node.exe\" \"C:\\Users\\Alexander\\Desktop\\web\\ahk\\phpstorm.js\" \"%1\""

phpstorm.js:

const child_process = require('child_process');
const fs = require('fs')

let path = process.argv[2]
path = path.replace('myproto://','')
path = decodeURIComponent(path)
path = path.replace(/\/$/,'')

ls = child_process.exec('"C:\\Program Files\\JetBrains\\PhpStorm 2019.1.1\\bin\\phpstorm64.exe" ' + path + '')

php.ini:

xdebug.file_link_format = "myproto://%f:%l"

edited Oct 17, 2019 at 13:32

answered Oct 17, 2019 at 13:25

Alexander Myravjev

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