working with array of objects with conditions

Question

Here we have an array of objects:

var slides = [
{ id: 1, performance: 20, guided_phrases: ["I was sent", "I don't know"] },
{ id: 2, performance: 30, guided_phrases: ["to earth"] },
{ id: 3, performance: 40, guided_phrases: ["to protect you"] },
{ id: 4, performance: 15, guided_phrases: ["I was sent"] },
{ id: 5, performance: 50, guided_phrases: ["I was sent"] }
];

I want to find the id of the slide which its guided_phrases includes a specific string (represented in phrase variable ) with the lowest performance...

So if we have let phrase = "I was sent"; then the output should be slide id 4 because the performance is the lowest among slides 1 and 4 and 5.

I have tried this code but I need a hand to figure out a simple way to log the id:

let phrase = "I was sent";
let contain = [];
for(let i = 0; i < slides.length; i++){

   if(slides[i].guided_phrases.includes(phrase)){

     contain.push(slides[i].performance)
     console.log(contain)
     let max = Math.min.apply(null, contain); 
     console.log(max)
   }
}

You would not need to store the performances in the contain array. You should store only the last object (or its index) in a variable, then update that whenever you find a matching one with better performance than the last. Then log its id afterwards. — Bergi
– Bergi, Commented Oct 9, 2019 at 19:04
Are you going to search for phrase multiple times? If yes, you could create an object or a Map with each unique phrase as key and the id of the lowest performance as it's value. Now you could get the value with just mappingObject[phrase] — adiga
– adiga, Commented Oct 9, 2019 at 19:16

omgitsgod · Accepted Answer · 2019-10-09 19:14:55Z

2

I would go with :

const slides = [
{ id: 1, performance: 20, guided_phrases: ["I was sent", "I don't know"] },
{ id: 2, performance: 30, guided_phrases: ["to earth"] },
{ id: 3, performance: 40, guided_phrases: ["to protect you"] },
{ id: 4, performance: 15, guided_phrases: ["I was sent"] },
{ id: 5, performance: 50, guided_phrases: ["I was sent"] }
];

const logID = (phrase) => {
  console.log(slides.filter(x => x.performance === Math.min(...slides.filter(slide => slide.guided_phrases.includes(phrase)).map(x => x.performance)))[0].id);
}

logID('I was sent');

answered Oct 9, 2019 at 19:14

omgitsgod

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Comments

Abdelillah Aissani · Accepted Answer · 2019-10-09 19:14:12Z

2

Here is a possible solution using some ES6:

var slides = [
{ id: 1, performance: 20, guided_phrases: ["I was sent", "I don't know"] },
{ id: 2, performance: 30, guided_phrases: ["to earth"] },
{ id: 3, performance: 40, guided_phrases: ["to protect you"] },
{ id: 4, performance: 15, guided_phrases: ["I was sent"] },
{ id: 5, performance: 50, guided_phrases: ["I was sent"] }
];

let phrase = "I was sent";

const findLowestId = (arr) => slides.filter(x => {
   const reg = new RegExp(phrase)
   return x.guided_phrases.find(y=> y.match(reg)) 
}).sort((a,b)=> a.performance > b.performance)[0].id

console.log(findLowestId(slides))

answered Oct 9, 2019 at 19:14

Abdelillah Aissani

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Comments

Diamond · Accepted Answer · 2019-10-09 19:27:44Z

2

I used only one loop.

var slides = [
{ id: 1, performance: 20, guided_phrases: ["I was sent", "I don't know"] },
{ id: 2, performance: 30, guided_phrases: ["to earth"] },
{ id: 3, performance: 40, guided_phrases: ["to protect you"] },
{ id: 4, performance: 15, guided_phrases: ["I was sent"] },
{ id: 5, performance: 50, guided_phrases: ["I was sent"] }
];

const search = 'I was sent';

let result = -1;
let performance = 0;
slides.forEach((slide, index) => {
  if(slide.guided_phrases.includes(search) > -1 && performance < slide.performance) {
    performance = slide.performance;
    result = index;
  }
});

console.log('Result:', result);

answered Oct 9, 2019 at 19:27

Diamond

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Comments

Matt Aft · Accepted Answer · 2019-10-09 19:30:08Z

2

This is how I would do it if you want a function that's readable and easy to follow:

const lowestPerformance = (slides, phrase) => {
    let currLowest = null;

    for (let i = 0; i < slides.length; i++) {
        let slide = slides[i];

        if (slide.guided_phrases.includes(phrase)) {
            currLowest =  ((currLowest === null) || slide.performance < (currLowest.performance)) ? slide : currLowest;
        }
    }

    return currLowest;
}

answered Oct 9, 2019 at 19:30

Matt Aft

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Comments

chans · Accepted Answer · 2019-10-09 19:17:18Z

1

let phrase = "I was sent";
let contain = null;
let id = null;
for(let i = 0; i < slides.length; i++){

   if(slides[i].guided_phrases.includes(phrase)){
     if (contain == null) {
       contain = slides[i].performance;
       id = slides[i].id;
     } else {
       if (contain > slides[i].performance) {
         contain = slides[i].performance;
         id = slides[i].id;
       }
     }
  }
}
console.log(id);

answered Oct 9, 2019 at 19:17

chans

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