I'm trying to figure out how i can convert a complex hash like this:
{
["A", "B"]=>{"id"=>123,"name"=>"test"},
["A", "F"]=>{"id"=>236,"name"=>"another test"},
["C", "F"]=>{"id"=>238,"name"=>"anoother test"}
}
into an even more complex hash like
{
"A"=>{
"B"=>{"id"=>123,"name"=>"test"},
"F"=>{"id"=>236,"name"=>"another test"}
},
"C"=>{
"F"=>{"id"=>238,"name"=>"anoother test"}
}
}
Any help would be really welcome!
each_with_object could be the rescue:
hash.each_with_object(Hash.new {|h, k| h[k] = {}}) do |((first, last), v), memo|
memo[first].merge!(last => v)
end
#=> {"A"=>{"B"=>{"id"=>123, "name"=>"test"},
# "F"=>{"id"=>236, "name"=>"another test"}},
# "C"=>{"F"=>{"id"=>238, "name"=>"anoother test"}}}
Array#{first/last} you can tell Ruby to decompose k: |((k1, k2), v), memo|. Depending on the actual data you can even give it a more fitting name than k2 (or k.last).You can also use Enumerable#group_by then Hash#transform_values by Enumerable#map to a new hash using Array#to_h:
h.group_by { |h,k| h.first }.transform_values { |v| v.map { |a, b| [a.last, b] }.to_h }
