While loop not looping - Python

Question

A while loop in my code is not looping.

I've tried ensuring the while loop would loop but no loop was executed.

#Name_Input
login = 1
while login == 1:
    print("Enter the username and password \n")
    username = input("Username: ")
    password = input("Password: ")
    if password and username != "cameron" and "123":
        print("\nWrong username or password... \nTry Again...")
        login = 1

I am expecting the loop to go back to the login when the login details are entered incorrectly.

The condition in your if doesn't work as you expect. You need to do something like if condition_1 or condition_2 — Some programmer dude
– Some programmer dude, Commented Sep 30, 2019 at 10:36
@owninggreendragsdude because 1 is a boolean value. Actually all objects in Python have a boolean value, the bool type was a later (and highly debated FWIW) addition. — bruno desthuilliers
– bruno desthuilliers, Commented Sep 30, 2019 at 11:38
@owninggreendragsdude also the OP may have a need for more than possible 2 values here (I fail to imagine why but we only have a short excerpt of the real code) ;-) — bruno desthuilliers
– bruno desthuilliers, Commented Sep 30, 2019 at 11:40

vBrail · Accepted Answer · 2019-09-30 10:43:41Z

2

login = 1
while login == 1:
    print("Enter the username and password \n")
    username = str(input("Username: "))
    password = str(input("Password: "))
    if username  ==  "cameron" and   password == "123":
        login=2
    else:
        print("\nWrong username or password... \nTry Again...")

answered Sep 30, 2019 at 10:43

vBrail

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Comments

Paolo Mossini · Accepted Answer · 2019-09-30 10:45:27Z

1

Try this if syntax:

login = 1
while login == 1:
    print("Enter the username and password \n")
    username = input("Username: ")
    password = input("Password: ")
    if password !=  "123" or username != "cameron":
        print("\nWrong username or password... \nTry Again...")
        login = 1
    else:
        login = -1

edited Sep 30, 2019 at 10:45

answered Sep 30, 2019 at 10:36

Paolo Mossini

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1 Comment

Some programmer dude Over a year ago

The condition still won't work as the OP expects (I believe). Please read up on De Morgan's laws. And read the message being printed, it contains the right logic. :)

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