php xpath parse script src

Question

I am trying to parse all script src link values, but I get an empty array.

$dom = new DOMDocument();
$file = @$dom->loadHTML($remote);

$xpath = new DOMXpath($dom);

$link = $xpath->query('//script[contains(@src, "pcode")]');

$return = array();
foreach($link as $links) {
  $return[] = $links->nodeValue;
}

Without input sample this is not a real question. Besides that if those script have @src they shouldn't have content, you are using the wrong DOM method. See textContent from DOM level 3. — user357812
– user357812, Commented Apr 28, 2011 at 16:03
If by "link" you mean the src attribute, then you should be selecting them with //script/@src[contains(.,"pcode")]. — user357812
– user357812, Commented Apr 28, 2011 at 19:40

shmeeps · Accepted Answer · 2011-04-28 04:01:45Z

2

Your XPATH query looks valid, should grab every <script> with attribute src containing pcode.

If it's returning an empty array, there's a few things to check:

Make sure the DOM document and loading, and there are not errors when loading it into XPATH. It could be possible that the suppressed DOM->load is giving an error or warning. If you query elsewhere and it works, then ignore this.

Make sure the tags in your document are case-matching.

Try

$link = $xpath->query("//script[contains(@src, 'pcode')]");

Seems silly, just switching quote marks, but you never know.

answered Apr 28, 2011 at 4:01

shmeeps

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Comments

William Walseth · Accepted Answer · 2011-12-14 15:52:43Z

1

Be sure to check namespaces. If your HTML contains a declaration like this

<html xmlns="http://www.w3.org/1999/xhtml">

You'll need to register the namespace with the document

$xp = new domxpath( $xml);
$xp->registerNamespace('html', 'http://www.w3.org/1999/xhtml' );

And Look for elements like this

$elements = $xp->query( "//html:script", $xml );

Namespaces, because paranoia breeds confidence.

answered Dec 14, 2011 at 15:52

William Walseth

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