execute one line of python with variable input from bash

Question

I want to write one line of python and wrap in such a way than it will run from bash. I looked into it and the idea seemd possible but, I'd specifically like to incorporate a variable input.

As an illustrative example; Here's what worked:

python -c "print('my favorite number to itself is '+str(5**5))"

However, I'd like to have a variable input so I tried to pipe one in, but the following doesn't work:

5 | python -c "print('my favorite number to itself is '+str($1**$1))"

What can I do to keep it simple, keep it one line, and add a variable input?

Cyrus · Accepted Answer · 2019-09-22 01:41:40Z

2

You could do:

i=5; python -c "print('my favorite number to itself is '+str($i**$i))"

edited Sep 22, 2019 at 1:41

Cyrus

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answered Sep 22, 2019 at 1:36

choltreppe

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Comments

Cyrus · Accepted Answer · 2019-09-22 01:43:10Z

1

With xargs:

echo 5 | xargs -I {} python -c "print('my favorite number to itself is '+str({}**{}))"

answered Sep 22, 2019 at 1:43

Cyrus

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