How to substitute a value in an array with an array of values

Question

I have an array of values, for example

$fred = Array('one','two','@group','three','four');

and a second array

$group = Array('alpha','beta','gamma');

Which is the most efficient way to substitute the value '@group' with the values inside $group array? That is, to obtain

$expanded_fred = Array('one','two','alpha','beta','gamma','three','four');

PS The grouping method has only one level. No nested groups.

cOle2 · Accepted Answer · 2019-09-19 21:19:11Z

2

First lets use array_search to find the key of the @group element:

$replaceKey = array_search('@group', $fred);

Next we'll use array_splice to replace the @group element with the $group array:

array_splice($fred, $replaceKey, 1, $group);

$fred is now your expanded array.

Demo here: https://3v4l.org/qf4ts

answered Sep 19, 2019 at 21:19

cOle2

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1 Comment

LF-DevJourney Over a year ago

There may be more @group in $fred.

LF-DevJourney · Accepted Answer · 2019-09-20 00:27:29Z

2

You can iterate the $fred to find all @group to replace them with $group. Demo

$result = [];
$fred = Array('one','two','@group','three','four');
$group = Array('alpha','beta','gamma');
foreach($fred as $value){
    if($value == '@group'){
        $result = array_merge($result,$group);
    }else{
        $result[] = $value;
    }
}
print_r($result);

answered Sep 20, 2019 at 0:27

LF-DevJourney

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