Find multiple string from a given string using regex

Question

s = "[(0, '0.105*\"function\" + 0.032*\"program\" + 0.024*\"location\"')]"

This is a string I have. How do I separate strings like "function", "program", "location" using regex in python?

I expect the output in terms of list i.e.

lst = ['function', 'program', 'location']

Anything wrong with using the regex function|program|location? — MonkeyZeus
– MonkeyZeus, Commented Aug 15, 2019 at 12:05
Regex is the wrong tool for parsing expressions. You want a parser (though a regex-based lexer can be a useful component in that overall architecture). — tripleee
– tripleee, Commented Aug 15, 2019 at 12:22

ForceBru · Accepted Answer · 2019-08-15 12:08:45Z

1

Try this:

>>> re.findall(r'"([^"]*)"', s)
['function', 'program', 'location']

answered Aug 15, 2019 at 12:08

ForceBru

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Daweo · Accepted Answer · 2019-08-15 13:30:52Z

1

You can use re module for that, but - at least for that sample data you provided - do not have to use it to get desired output, as just str methods will suffice. That is:

s = "[(0, '0.105*\"function\" + 0.032*\"program\" + 0.024*\"location\"')]"
lst = [i for i in s.split('"') if i.isalpha()]
print(lst)

Output:

['function', 'program', 'location']

This code simply split s at " and then pick strs which consist solely of alphabetic characters and have length no less than 1.

answered Aug 15, 2019 at 13:30

Daweo

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Marek Maszay · Accepted Answer · 2019-08-15 12:08:39Z

0

import re
s = "[(0, '0.105*\"function\" + 0.032*\"program\" + 0.024*\"location\"')]"
groups = re.findall("\"([a-z]+?)\"",s) # get groups of all letters which are between two `"`
print(groups) # -> ['function', 'program', 'location']

answered Aug 15, 2019 at 12:08

Marek Maszay

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