Python-Gitlab list projects and groups by name

Question

I am trying to list the project list by names not by ID#. This goes the same with listing the groups by name not by ID#.

I tried running some python-gitlab codes with python 2.7 version but I only get the ID#.

projects = gl.projects.list()
groups = gl.groups.list()

These two lines only gives the ID# of the projects and the groups but that's not what I want. What I want to know if it's possible to only get the name listed in groups and projects. Is that possible?

Thomas Kainrad · Accepted Answer · 2019-08-14 12:31:53Z

2

There is an attribute called "attributes". Try the following:

for project in gl.projects.list():
    # print everything
    print(project.attributes)
    # or a single attribute
    print(project.attributes['name'])

The same for groups:

for group in gl.groups.list():
    # print everything
    print(group.attributes)
    # or a single attribute
    print(group.attributes['name'])

answered Aug 14, 2019 at 12:31

Thomas Kainrad

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3 Comments

Woods Over a year ago

This works great! How would you return the list as the print statement prints the list of project names and group names? I tried the return statement but I cannot get the list as print statement would do it. I tried with append syntax as well but I am not getting it right. I get [u'pro1', u'pro2', ..] I just one something like... pro1 and pro2 like a list.

Thomas Kainrad Over a year ago

It is not clear to me what your current problem is. You already tried to append to a list within the for loop? Initializing a list before the loop and then doing myList.append(group.attributes['name']) in the loop should work.

Woods Over a year ago

I am coming back to this. Why does this even print the subgroups as well? I only want to print the groups not the subgroups from git site.

Ramesh Reddy · Accepted Answer · 2020-12-10 05:12:59Z

0

Use pagination if you have more than 20 projects in the group

    gl = gitlab.Gitlab('https://gitlab.com', private_token='Token')
    group = gl.groups.get(group_id, lazy=True)
    project_lst=group.projects.list(as_list=False)  #pagination
    for item in project_lst:
        project_id = gl.projects.get(item.attributes['id'])
        ......................................
        ......................................

answered Dec 10, 2020 at 5:12

Ramesh Reddy

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