Difficulty converting array to string

Question

how can i convert this array to string?

public static function generos($string) {
   return preg_replace(array("/(natacao)/"),explode(" ","Natação"), $string);
}

public function categoria($string) {
    $this->exp = explode(",", $string);
    foreach ($this->exp as $this->list) :
        return $this->generos(implode(",", $this->list));
    endforeach;
}

echo '<li>'.$this->categoria($rows[] = $this->row['categoria']).'</li>';

table

id  |  categoria  
 1  |  futebol, voleiball

Current results

<li>futebol, voleiball</li>

expected result

<li>futebol</li>
<li>voleiball</li>

Where is <li> and </li> coming from? I don't see it anywhere in the code. — Barmar
– Barmar, Commented Aug 12, 2019 at 18:11
The return statement is ending the foreach loop during the first iteration. I don't see how you're getting both futebol and voleiball in the output. — Barmar
– Barmar, Commented Aug 12, 2019 at 18:12
It's generally not a good idea to store comma-separated lists in a database column. You should normalize your data. But that's a separate issue from this problem. — Barmar
– Barmar, Commented Aug 12, 2019 at 18:13

Micheal Don · Accepted Answer · 2022-04-09 22:41:34Z

1

add your array's value to another variable like this:

<?php
    $dizi=array('mother','father','child'); //This is array

    $sayi=count($dizi);
    for ($i=0; $i<$sayi; $i++) {
        $dizin.=("'$dizi[$i]',"); //Now it is string...
    }
         echo substr($dizin,0,-1); //Write it like string :D
?>

In this code we added $dizi's values and comma to $dizin:

$dizin.=("'$dizi[$i]',");

Now

$dizin = 'mother', 'father', 'child',

It's a string, but it has an extra comma :)

And then we deleted the last comma, substr($dizin, 0, -1);

Output:

'mother','father','child'

answered Apr 9, 2022 at 22:41

Micheal Don

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