ASP .NET MVC - return Exception message to ajax call

Question

My ajax call:

  $.ajax({
     url: './Orders/SaveOrder',
     type: "POST",
     data: JSON.stringify(data),
     dataType: "JSON",
     contentType: "application/json",
     success: function (d) {
     if (d.status == true) {
          alert('Successfully saved.');
       }
       else {
             alert('Failed' + d.ErrorMessage);
        }
       },
       error: function (error) {
         alert('Error. Please try again.');
        }

And my SaveOrder controller action:

  [HttpPost]
  public JsonResult SaveOrder(OrderVM o)
  {
    try
            {
                if (ModelState.IsValid)
                {
                      // do some database work
                    }
                }

                return new JsonResult { Data = new { status = status} };
            }
            catch (Exception ex)
            {
                // how to return jsonresult with error?
            }
        }

How do I get the ajax request to receive the details from the try-catch catch block? Specifically how does the 'error: function...' section get the code back?

look here, see if it helps

Bosco
– Bosco

2019-07-25 22:08:32 +00:00
Commented Jul 25, 2019 at 22:08 — Bosco
– Bosco, Commented Jul 25, 2019 at 22:08

Jason Roner · Accepted Answer · 2019-07-25 21:21:37Z

2

you can try:

return new HttpStatusCodeResult(500, ex.Message);

I believe this would work with Ajax and you can get the error message from the error parameter. Hope it works!

edit: For the ajax error, you can access the error message:

    error: function (error) {
        alert(error.statusText);
    }

edited Jul 25, 2019 at 21:21

answered Jul 25, 2019 at 20:46

Jason Roner

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2 Comments

John M Over a year ago

I tried that but the method expects a Jsonresult to be returned.

Jason Roner Over a year ago

Change the return type of the method to ActionResult, and you can still use JsonResult along with returning a StatusCode() for your errors.

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