loop with array data

Question

i have this code to get three values.

 success: function(json){
                        $msg1 = parseFloat(json[0].valor1);
                        $msg2 = parseFloat(json[1].valor2);
                        $msg3 = parseFloat(json[2].valor3);
                    }

but now suppose that i need 200 values. I'm not doing 200 times ...

                        $msg1 = parseFloat(json[0].valor1);
                        $msg2 = parseFloat(json[1].valor2);
                        $msg3 = parseFloat(json[2].valor3);
                        //...
                        $msg200 = parseFloat(json[199].valor200);

so, i need a loop, correct?

i tried something like this

                        for (i=0; i<200; i++) {
                        $msg(i+1) = parseFloat(json[i].valor(i+1));
                        i++;
                        }

but didn't work

thanks

Why do you need 200 variables? Why not have one array with 200 elements? — lonesomeday
– lonesomeday, Commented Apr 19, 2011 at 14:10

Pointy · Accepted Answer · 2011-04-19 14:44:33Z

4

This is why The Creator gave the world arrays.

var msgs = [];
for (var i = 0; i < 200; ++i)
  msgs.push(parseFloat(json[i]['valor' + i]));

Note that your JSON data should also keep those "valor" properties as arrays, though in JavaScript you can deal with a bizarre naming scheme like that as in the example above.

edit — oops, typos fixed :-)

edited Apr 19, 2011 at 14:44

answered Apr 19, 2011 at 14:09

Pointy

415k62 gold badges600 silver badges631 bronze badges

Sign up to request clarification or add additional context in comments.

6 Comments

daniel__ Over a year ago

you code give me an error syntax - javascriptlint.com/online_lint.php. i think you forget a ]

daniel__ Over a year ago

no problem :) one more question please Pointy. Anteriorly i access to the values with y: $msg1. With your code, how i do? i try $msg[i]= msgs.push(// but i get $msg is not defined error

Pointy Over a year ago

Well if you set this up as an array, then it would be "msgs[1]" instead of "msgs1".

daniel__ Over a year ago

i just copy paste your code and change the y:$msg1 to y: msgs[0], and i get msgs is not defined y: msgs[0],

Pointy Over a year ago

@Wire Creation OK two things: first, move the definition of "msgs" (the var msgs = []; line) outside of the "$(document).ready()" block. Second thing is that you will have to delay the dojo setup code that uses "msgs" until after the ajax call completes. Maybe put it in a function and call it from the ajax handler. (If it's not clear you should probably post a separate question about that part.)

|

Headshota · Accepted Answer · 2011-04-19 19:25:30Z

1

$msg = [];
for (var i=0; i<200; i++) {
    $msg.push(parseFloat(json[i]["valor"+i]));       
}

edited Apr 19, 2011 at 19:25

answered Apr 19, 2011 at 14:10

Headshota

21.4k13 gold badges63 silver badges82 bronze badges

Comments

Marino Šimić · Accepted Answer · 2011-04-19 14:09:54Z

0

As stated by Pointy or:

                var msgs = [];
                for (i=0; i<200; i++) {
                $msg[i] = parseFloat(eval('json[' + i + '].valor(' + i + '+1)'));
                i++;
                }

However eval is slow, so Pointy's answer is better.

answered Apr 19, 2011 at 14:09

Marino Šimić

7,3801 gold badge34 silver badges66 bronze badges

1 Comment

Pointy Over a year ago

But what exactly is "$msg(i+1)" supposed to do?

James Kyburz · Accepted Answer · 2011-04-19 14:19:17Z

0

var array = json.someid;// or json['someid'];
// json is returned not an array
var msgs = [];
$.each(array, function(index, e) {
    msgs.push(parseFloat[e['valor' + index], 10); 
});

when using parseFloat use the radix parameter unless you want bad things to happen;

javascript needs to be told for example not to parse octal;

answered Apr 19, 2011 at 14:19

James Kyburz

14.6k1 gold badge34 silver badges33 bronze badges

Collectives™ on Stack Overflow

loop with array data

4 Answers 4

6 Comments

Comments

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

6 Comments

Comments

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related