For example, I want a string "1:00 pm 2:00 pm 3:00 pm" to turn into an array of a string of ["1:00 pm", "2:00 pm", "3:00 pm"]
I've tried using split. But it would produce ["1:00", "pm", "2:00", "pm", "3:00", "pm"]. How would I split every other space? Thank you.
split using regular expression, Regular expression (?<=m) to split the string using m as delimiter and including it. But there will be extra empty character from second element you can use trim() method to remove it
String s = "1:00 pm 2:00 pm 3:00 pm";
String[] arr = s.split("(?<=m)");
System.out.println(Arrays.toString(arr)); //[1:00 pm, 2:00 pm, 3:00 pm]
For your problem I might suggest using a formal Java regex matcher. The reason for this is that perhaps your time strings could appear as part of a larger string.
String input = "1:00 pm 2:00 pm 3:00 pm";
String pattern = "(?i)\\d{1,2}:\\d{2} [ap]m";
Pattern r = Pattern.compile(pattern);
Matcher m = r.matcher(input);
while (m.find()) {
System.out.println("Found a time: " + m.group(0));
}
This prints:
Found a time: 1:00 pm
Found a time: 2:00 pm
Found a time: 3:00 pm
You could use Java's indexOf method to find the index of each space and only take into account every other one. Then, create a sub string using your knowledge of the spaces and add it to your array.
