syntax error throwing up while comparing in python

Question

I have the following code

n = int(input())
s = set(map(int, input().split()))
N= int(input())

for i in range(1,N+1):
    ops=input()
    li=ops.split(' ')

    if li[0]=='pop':
        s.pop()
    elif li[0]=='discard':

        s.discard(int(li[1])
    elif li[0]=='remove':
       if (li[1]) in s:
            s.remove((li[1])


print(sum(s))

here I tried comparing the string I have in the li[0] with 'remove' but it throws an syntax error:

$python3 main.py
  File "main.py", line 14
    elif li[0]=='remove':
       ^
SyntaxError: invalid syntax

I am unable to find out where am I going wrong. Can you figure it out?

Stefan · Accepted Answer · 2019-06-28 18:21:56Z

2

It's in the line above, and below, print misses the closing )

print(1)

And

print(2)

update

Also your new code misses a ), twice

s.discard(int(li[1]))

And, here's actually a ( too many

s.remove(li[1])

edited Jun 28, 2019 at 18:21

answered Jun 28, 2019 at 18:14

Stefan

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2 Comments

DrZoo Over a year ago

Same with print(2)

Ankit Over a year ago

Yeah.. I get that.. My Bad :|

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