Check if an array contains any element of another array with some null in JavaScript

Question

I have a target array example: ["Potato", "Orange"] . I'm making an api call that return an object with multiple array which I have to look if the array contain any one of the target array elements.

I have the following Piece of code, but I get following error : Uncaught TypeError: Cannot read property 'includes' of null

I know this is because The object contains some Null values. How Can I fix this?

Example:    const myArray = [
   {
    Track: ["Potato", "Apple"],
           ["Banna"],
           ["Potato", "Batman", "Orange"]
     Type: ["Some", "Stuff"]
     },
   {
    Track: null
     Type: ["Some", "Stuff"]
     }
    ]

const value = "Potato"

const matchingSession = myArray.filter((obj) => value.some(x => { return obj.types.includes(x) || obj.tracks.includes(x)}));

Which it should Return :

[
["Potato", "Apple"],
["Potato", "Batman", "Orange"]
]

This is just an example. It could have more then one object in the array.

You do not have any properties anywhere named types (nor tracks). Your input also isn't valid Javascript, arrays cannot have key-value pairs — CertainPerformance
– CertainPerformance, Commented Jun 27, 2019 at 21:38
This has nothing to do with promises or Node.js. Unless your question is specifically about those tags, please do not use them. — Patrick Roberts
– Patrick Roberts, Commented Jun 27, 2019 at 21:38
@CertainPerformance Yes You are right sorry for my poorly example. I just edited, close to what I'm currently getting. Thanks — Mandoxsy
– Mandoxsy, Commented Jun 27, 2019 at 21:54

Jamal Abo · Accepted Answer · 2019-06-27 22:25:29Z

3

myArray.filter((arr) => Array.isArray(arr) && arr.length > 0)

This line checks if the array object is a type of array and not empty

Edit

const arrayOfValues = ["Potato", "Apple"];
myArray.filter((arr) => {

    return Array.isArray(arr) && CheckArray(arrayOfValues, arr) && arr.length > 0
});
function CheckArray(Array, ArrayToCheck) {
    let found = false;
    for (const value of Array) {
        if (ArrayToCheck.includes(value)) {
            found = true;
        }
    }
    return found;
}

Checks if an array includes one of arrayOfValues and if the object is an array and not empty!

Edit 2

const myArray = [
  {
    Track: ["Potato", "Apple"],
    data: [["Banna"],
      ["Potato", "Batman", "Orange"],
      ["Some", "Stuff"]],
  },
  {
    Tack: null,
    data: ["Some", "Stuff"],
  },
];
myArray.map((arr) => {
  return Array.isArray(arr.data) && CheckArray(arr.Track, arr.data);
}).filter(_ => !!_);

function CheckArray(arr, ArrayToCheck) {
  if (!arr || !Array.isArray(arr)) {
    return ArrayToCheck;
  }
  const foundArray = [];    
  if (ArrayToCheck.every(item => Array.isArray(item))) {
    for (const subArr of ArrayToCheck) {
      const ResultArray = CheckArray(arr, subArr);
      if (ResultArray.length > 0) {
        foundArray.push(ResultArray);
      }
    }
  } else {
    if (ArrayToCheck.map(val => arr.includes(val)).includes(true)) {
      foundArray.push(ArrayToCheck);
    }
  }
  return foundArray;
}

Checks if an array includes one of Track data, (works for sub-arrays (2d, etc..))

edited Jun 27, 2019 at 22:25

answered Jun 27, 2019 at 21:40

Jamal Abo

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4 Comments

Mandoxsy Over a year ago

Thanks @JamalAbo I'll try this now! This is Great!

Jamal Abo Over a year ago

@Mandoxsy, ok, if it meets the requirements, don't forget to upvote and accept the answer!

Mandoxsy Over a year ago

will this code return a new array with matching element? or just bolean?

Jamal Abo Over a year ago

@Mandoxsy all codes return matched arrays, (and edit 2 -> for what meets Track requirements)

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