Accessing objects within objects

Question

var data = {
     row: row,
     row2: row2
};

var tableData = [data.row,data.row2];

row objects contains lot of children objects too... now how would i placed my tableData to access each single objects. so it goes like this...

var tableData = [data.row[1],data.row[2],data.row[3],,data.row2];

Updated Question

var data = [row, row2];

In this case how would i access my row children objects.

you asked that second part already: stackoverflow.com/questions/5668833/… — Naftali
– Naftali, Commented Apr 14, 2011 at 20:24

Raynos · Accepted Answer · 2011-04-14 20:32:50Z

1

var data = {key: value, ... };

var tableData = [];
for (var k in data) {
    for (var i = 0, len = data[k].length; i < len; i++)) {
        tableData.push(data[k][i]);
    }
}

Use nested for loops and array.prototype.push

Edit

for (var j = 0, len = data.length;j < len;j++) {
    for (var i = 0, len = data[j].length; i < len; i++)) {
        tableData.push(data[j][i]);
    }
}

You can replace for (var j in data) with for (var j = 0, len = data.length; j < len; j++)

The latter

sets j to 0
caches the length so you only ask for the length once.
Checks that j is not bigger then the amount of elements in your array
Increases j when you get to the end of the block.

edited Apr 14, 2011 at 20:32

answered Apr 14, 2011 at 20:13

Raynos

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4 Comments

theJava Over a year ago

One question what if my data is not an Json Object and instead its an Array of Object like this var data = [row, row2];

Raynos Over a year ago

@TheJava then it still works. As long as each row is also an Array. You may want to convert the for in loop into normal for loop.

Raynos Over a year ago

@theJava how lazy are you? it's a simple change. Take your hands out of your pocket.

theJava Over a year ago

if i had know i would have not asked

Billy Moon · Accepted Answer · 2011-04-14 20:14:24Z

1

Assign data.row first, then push data.row2, like this:

var tableData = data.row
tableData.push(data.row2)

answered Apr 14, 2011 at 20:14

Billy Moon

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5 Comments

Raynos Over a year ago

That's the same as var tableData = [data.row,data.row2]; he already got that far.

Billy Moon Over a year ago

Not the same, assuming row1 = [a,b,c]; row2 = [d] his produces [[a, b, c], d] and mine produces [a, b, c, d] which I think is what he is after.

Raynos Over a year ago

true that would work. But only in a very specific case, that does not scale beyond his trivial example.

Billy Moon Over a year ago

@Raynos I am only trying to answer his question here - answers to other questions can found on other question's pages. The example given may not be trivial to @theJava.

Raynos Over a year ago

I meant he gave an example of his data rather then the actual data.The actual data probably has more elements.

Hristo · Accepted Answer · 2011-04-14 20:22:57Z

How about something like this...

var data = {
    letters : ["a", "b", "c"],
    numbers : ["0", "1", "2", "3"]
};

data.letters; // ["a", "b", "c"]
data.letters[0]; // "a"
data.numbers; // "0", "1", "2", "3"]
data.numbers[2]; // "2"

... or you could try this...

var data = {
    letters : new Array("a", "b", "c"),
    numbers : new Array("0", "1", "2", "3")
};

data.letters; // ["a", "b", "c"]
data.letters[0]; // "a"
data.letters.push("d"); // the array is now ["a", "b", "c"]

data.numbers; // ["0", "1", "2", "3"]
data.numbers[2]; // "2"
data.numbers.pop(); // the array is now ["0", "1", "2"]

For more info on JavaScript arrays, check out these links:

I hope this helps.
Hristo

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